使用C++实现一个矩形类根据矩形左下角和右上角两个坐标求出面积

题目：

设计一个Rectangle类，属性为矩形的左下角与右上角两个坐标，计算矩形面积。

题目分析：

可知根据题目要求需先定义一个点类用于存储两个点的坐标

[code]class Point2
{
public:
int x;
int y;

void setPoint2(int xx, int yy)
{
this->x = xx;
this->y = yy;
}

};

然后定义一个Rectangle类

[code]class Rectangle
{
public:
Point2 rightPoint;
Point2 leftPoint;
Rectangle(int rx, int ry, int lx, int ly)
{
rightPoint.setPoint2(rx, ry);
leftPoint.setPoint2(lx, ly);
}

int Area()
{
int length = abs(rightPoint.x - leftPoint.x);
int width = abs(rightPoint.y - leftPoint.y);
return length * width;
}
};

完整代码如下

[code]#include <iostream>
using namespace std;

class Point2
{
public:
int x;
int y;

void setPoint2(int xx, int yy)
{
this->x = xx;
this->y = yy;
}

};

class Rectangle
{
public:
Point2 rightPoint;
Point2 leftPoint;
Rectangle(int rx, int ry, int lx, int ly)
{
rightPoint.setPoint2(rx, ry);
leftPoint.setPoint2(lx, ly);
}

int Area()
{
int length = abs(rightPoint.x - leftPoint.x);
int width = abs(rightPoint.y - leftPoint.y);
return length * width;
}
};

int main()
{
Rectangle r1(0,4,4,0);

cout << "面积为：" << r1.Area() << endl;

return 0;
}