C语言实现简单万年历

本文实例为大家分享了C语言实现简单万年历的具体代码，供大家参考，具体内容如下

#include <stdio.h>
#include<stdlib.h>
int year, month;
int run[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 };
int ping[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };
char week[7][10] = { "SUN","MON","TUE","WED","THU","FRI","SAT" };

bool IsLeap(int year)
{
if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) //判断闰年
{
return true;
}
else
{
return false;
}
}
void PrintStar()
{
printf("\t\t\t万年历\t\t\t\n");
printf("****************************************************\n");
for (int i = 0; i < 7; i++)
{
printf("%s\t", week[i]);
}
printf("\n");
}
int DaySum(int year, int month)
{
int sum = 0;
for (int i = 1990; i < year; i++)
{
if (IsLeap(i))
{
sum += 366;
}
else
{
sum += 365;
}
}
for (int i = 0; i < month - 1; i++)
{
if (IsLeap(year))
{
sum += run[i];
}
else
{
sum += ping[i];
}
}
return sum;
}

void PrintCal(int sum, int year, int month)
{
int nRes, nTmp;
nRes = sum % 7+1;//前面空几格
nTmp = 7 - nRes;//从第几格开始打印
for (int i = 0; i < nRes; i++)
{
printf("\t");
}
if (IsLeap(year))
{
for (int i = 1; i < run[month - 1]+1; i++)
{
printf("%d\t", i);
if (nTmp == i || (i - nTmp) % 7 == 0)
{
printf("\n");
}
}
printf("\n");
}
else
{
for (int i = 1; i < ping[month - 1]+1; i++)
{
printf("%d\t", i);
if (nTmp == i || (i - nTmp) % 7 == 0)
{
printf("\n");
}
}
printf("\n");
}

}
int main(void)
{
while (1)
{
scanf_s("%d %d", &year, &month);
PrintStar();
PrintCal(DaySum(year, month), year, month);
printf("****************************************************\n");
}

return 0;

}

以上就是本文的全部内容，希望对大家的学习有所帮助

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