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Java实现扑克牌洗牌和发牌

2020-04-06 12:06 1936 查看

本文实例为大家分享了Java实现扑克牌洗牌发牌的具体代码,供大家参考,具体内容如下

实现原理:使用4种花色和13个数字组合成52张牌,放进一个集合中;通过把集合数据排序打乱实现洗牌操作,然后在通过循环把牌抽出来实现发牌操作。

下面是实现代码:

import java.util.ArrayList;
import java.util.Collections;

public class Card {
private static ArrayList<String> list = new ArrayList<>();
private static String[] colors = {"黑桃","红桃","梅花","方块"};
private static String[] nums = {"A","2","3","4","5","6","7","8","9","10","J","Q","K"};
private static String[] jokers = {"Joker","joker"}; //大小王
private static ArrayList<String> A = new ArrayList<>(); //小人A
private static ArrayList<String> B = new ArrayList<>(); //小人B
private static ArrayList<String> C = new ArrayList<>(); //小人C
private static ArrayList<String> D = new ArrayList<>(); //小人D

//初始化扑克牌
public static void initCards(boolean need){
for(String color:colors){
for (String num:nums) {
list.add(color + num);
}
}
//是否添加大小王
if (need) {
list.add(jokers[0]);
list.add(jokers[1]);
}
}

//洗牌
public static void xiPai(){
Collections.shuffle(list);
}

//性感荷官,在线发牌
public static void faPai(){
A.clear();
B.clear();
C.clear();
D.clear();
for (int i = 0; i < list.size();i++) {
if (i%4 == 0) {
A.add(list.get(i));
}
if (i%4 == 1) {
B.add(list.get(i));
}
if (i%4 == 2) {
C.add(list.get(i));
}
if (i%4 == 3) {
D.add(list.get(i));
}
}
}

//主方法
public static void main(String args[]){
initCards(true);
xiPai();
faPai();
System.out.print("小人A" + A + "\n");
System.out.print("小人B" + B + "\n");
System.out.print("小人C" + C + "\n");
System.out.print("小人D" + D + "\n");
}
}

下面是运行结果

以上就是本文的全部内容,希望对大家的学习有所帮助

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标签:  java 扑克牌