-1. 旧的解决方法(sql server 2000)

  create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go   --方法1.使用临时表完成 SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b    SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(',', A.[value] + ',', B.id) - B.id) FROM tb A, # B WHERE SUBSTRING(',' + A.[value], B.id, 1) = ','   DROP TABLE #   --方法2.如果数据量小，可不使用临时表 select a.id , value = substring(a.value , b.number , charindex(',' , a.value + ',' , b.number) - b.number)  from tb a join master..spt_values  b  on b.type='p' and b.number between 1 and len(a.value) where substring(',' + a.value , b.number , 1) = ','   --2. 新的解决方法(sql server 2005) create table tb(id int,value varchar(30)) insert into tb values(1,'aa,bb') insert into tb values(2,'aaa,bbb,ccc') go   --方法1.使用xml完成 SELECT A.id, B.value FROM (   SELECT id, [value] = CONVERT(xml,'' + REPLACE([value], ',', '') + '') FROM tb ) A OUTER APPLY (   SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v) ) B   --方法2.使用CTE完成 ;with tt as  (select id,[value]=cast(left([value],charindex(',',[value]+',')-1) as nvarchar(100)),Split=cast(stuff([value]+',',1,charindex(',',[value]+','),'') as nvarchar(100)) from tb union all select id,[value]=cast(left(Split,charindex(',',Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(',',Split),'') as nvarchar(100)) from tt where split>'' ) select id,[value] from tt order by id option (MAXRECURSION 0)     DROP TABLE tb

转载于:https://www.cnblogs.com/lydg/p/11362555.html

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