再看go的interface代码示例

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       代码：

[code]package main
import "fmt"

type Base interface {
Input() int
}

type Dog struct {
}

func (p Dog) Input() int {
fmt.Println("call input dog")
return 100
}

func main() {
handler := func() Base { return Dog{} }
fmt.Printf("type: %T, %v\n", handler(), handler().Input())
}

        结果：

call input dog
type: main.Dog, 100

     

       代码：

[code]package main
import "fmt"

type Base interface {
Input() int
}

type Dog struct {
}

func (p Dog) Input() int {
fmt.Println("call input dog")
return 100
}

func main() {
handler := func() Base { return &Dog{} }
fmt.Printf("type: %T, %v\n", handler(), handler().Input())
}

       结果：

call input dog
type: *main.Dog, 100

      

      代码：

[code]package main
import "fmt"

type Base interface {
Input() int
}

type Dog struct {
}

func (p *Dog) Input() int {
fmt.Println("call input dog")
return 100
}

func main() {
handler := func() Base { return &Dog{} }
fmt.Printf("type: %T, %v\n", handler(), handler().Input())
}

       结果：

call input dog
type: *main.Dog, 100

 

       代码：

[code]package main
import "fmt"

type Base interface {
Input() int
}

type Dog struct {
}

func (p *Dog) Input() int {
fmt.Println("call input dog")
return 100
}

func main() {
handler := func() Base { return Dog{} }
fmt.Printf("type: %T, %v\n", handler(), handler().Input())
}

       结果：

# command-line-arguments
./a.go:17:40: cannot use Dog literal (type Dog) as type Base in return argument:
        Dog does not implement Base (Input method has pointer receiver)

 

      好好理解下。

 

 

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