您的位置:首页 > 理论基础 > 计算机网络

Asp 使用 Microsoft.XMLHTTP 抓取网页内容并过滤需要的

2018-10-12 14:06 483 查看
Asp 使用 Microsoft.XMLHTTP 抓取网页内容(没用乱码),并过滤需要的内容

示例源码:

<%
Dim xmlUrl,http,strHTML,strBody
xmlUrl = Request.QueryString("u")

REM 异步读取XML源
Set http = server.CreateObject("Microsoft.XMLHTTP")
http.Open "POST",xmlUrl,false
http.setrequestheader "User-Agent", "Mozilla/4.0"
http.setrequestheader "Connection", "Keep-Alive"
http.setRequestHeader "Content-Type", "application/x-www-form-urlencoded"
http.Send()

strHTML = BytesToBstr(http.ResponseBody)
set http = nothing

REM 抓取主要内容
strBody = GetBody(strHTML,"<div id=""Div_newsContentc"" class=""cnt"">","</div>",0,0)
strBody =Replace(strBody,"(本文首发于","")
strBody =Replace(strBody,"财富动力网</a>,转载请注明出处。)","")
strBody =Replace(strBody,"本文首发于,转载请注明出处。)","")
strBody =Replace(strBody,"财富动力网</a>:http://www.927953.com","")
strBody =Replace(strBody,"本文首发于","")

Response.Write RegRemoveHref(strBody)

REM 获取对应网址响应的HTML
Function BytesToBstr(body)
dim objstream
set objstream = Server.CreateObject("adodb.stream")
objstream.Type = 1
objstream.Mode =3
objstream.Open
objstream.Write body
objstream.Position = 0
objstream.Type = 2
objstream.Charset = "UTF-8"

'转换原来默认的UTF-8编码转换成GB2312编码,否则直接用
'XMLHTTP调用有中文字符的网页得到的将是乱码
BytesToBstr = objstream.ReadText
objstream.Close
set objstream = nothing
End Function


REM 使用正则表达式,抓取之内标记的内容
Function GetBody(ConStr,StartStr,OverStr,IncluL,IncluR)
If ConStr="$False$" or ConStr="" or IsNull(ConStr)=True Or StartStr="" or IsNull(StartStr)=True Or OverStr="" or IsNull(OverStr)=True Then
GetBody="$False$"
Exit Function
End If
Dim ConStrTemp
Dim Start,Over
ConStrTemp=Lcase(ConStr)
StartStr=Lcase(StartStr)
OverStr=Lcase(OverStr)
Start = InStrB(1, ConStrTemp, StartStr, vbBinaryCompare)
If Start<=0 then
GetBody="$False$"
Exit Function
Else
If IncluL=False Then
Start=Start+LenB(StartStr)
End If
End If
Over=InStrB(Start,ConStrTemp,OverStr,vbBinaryCompare)
If Over<=0 Or Over<=Start then
GetBody="$False$"
Exit Function
Else
If IncluR=True Then
Over=Over+LenB(OverStr)
End If
End If
GetBody=MidB(ConStr,Start,Over-Start)
End Function

REM 过滤a超链接
Function RegRemoveHref(HTMLstr)
Set ra = New RegExp
ra.IgnoreCase = True
ra.Global = True
ra.Pattern = "<a[^>]+>(.+?)<\/a>"

RegRemoveHref = Replace(ra.replace(HTMLstr,"$1"),"href=""http://www.927953.com""","")
END Function
%>

效果图如下: 
 

您可能感兴趣的文章:

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: