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关于线程锁的另外一个问题

2018-05-06 09:17 796 查看
多线程之间通过锁机制解决了共享资源的争夺,通常我们会使用某个具体的对象作为锁,那么,如果这个锁的值改变了?线程之间还会保持同步吗?

举例代码:

import java.util.Objects;

public class Operator {
private String id;
private String name;

public String getId() {
return id;
}

public void setId(String id) {
this.id = id;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Operator operator = (Operator) o;
return Objects.equals(id, operator.id) &&
Objects.equals(name, operator.name);
}

@Override
public int hashCode() {
return Objects.hash(id, name);
}
}

这是一个很普通的Java类。

接下来是对这个类操作的service:

public class OperatorService {

public void updateName(Operator operator) {
synchronized(operator) {
System.out.println("线程 :" + Thread.currentThread().getName() + " 进入");
System.out.println("operator对象name属性值:" + operator.getName());
operator.setName("test" + Math.random());
System.out.println("operator对象name属性值已更改:" + operator.getName());
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println(Thread.currentThread().getName() + "离开");
}
}
}

主运行入口:

public class Main {
public static void main(String[] args) throws Exception {
Operator operator = new Operator();
operator.setId("123");
operator.setName("123");

OperatorService service = new OperatorService();

new Thread(new ThreadA(operator, service)).start();
new Thread(new ThreadB(operator, service)).start();

}

static class ThreadA implements Runnable{
private Operator operator;
private OperatorService service;

public ThreadA(Operator operator, OperatorService service) {
this.service = service;
this.operator = operator;
}

@Override
public void run() {
service.updateName(operator);
}
}

static class ThreadB implements Runnable{
private Operator operator;
private OperatorService service;

public ThreadB(Operator operator, OperatorService service) {
this.service = service;
this.operator = operator;
}

@Override
public void run() {
service.updateName(operator);
}
}
}

这里的输出结果会是怎样的呢?输出结果如下:

线程 :Thread-0 进入
operator对象name属性值:123
operator对象name属性值已更改:test0.49531243439875083
Thread-0离开
线程 :Thread-1 进入
operator对象name属性值:test0.49531243439875083
operator对象name属性值已更改:test0.8638112164864292
Thread-1离开

虽然线程改变了锁的值,但是两个线程之间还是同步的。

总结:只要线程锁对象不变,锁对象的值改不改变,都不影响线程之间的同步效果。
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标签:  java 多线程