【PAT】L1-043. 阅览室【C语言实现】

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
int b[1005];
int main()
{
int n;
scanf("%d",&n);
int x,y,z;
char a[5];
int sum=0,s=0;
memset(b,-1,sizeof(b));
while(n--){
while(1){
scanf("%d %s %d:%d",&x,a,&y,&z);

if(x==0){
memset(b,-1,sizeof(b));
if(s!=0)
printf("%d %0.0f\n",s,(double)sum/s);
else
printf("0 0\n");
sum= s =0;
break;
}
else{
if(a[0]=='S'){
b[x] = y*60 + z ;
}
else if(a[0]=='E' && b[x] != -1){
s++;
sum += y*60 + z - b[x] ;
b[x]=-1;
}
}

}

}
return 0;
}