面向对象程序设计上机练习一(函数重载)(java)
2018-03-22 10:56
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import java.util.Scanner;
public class Main {
static int max(int a,int b,int c,int d,int e){
int max = a;
if(max < b) max = b;
if(max < c) max = c;
if(max < d) max = d;
if(max < e) max = e;
return max;
}
static long max(long a,long b,long c,long d,long e){
long max = a;
if(max < b) max = b;
if(max < c) max = c;
if(max < d) max = d;
if(max < e) max = e;
return max;
}
static float max(float a,float b,float c,float d,float e){
float max = a;
if(max < b) max = b;
if(max < c) max = c;
if(max < d) max = d;
if(max < e) max = e;
return max;
}
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int a1 = input.nextInt();
int b1 = input.nextInt();
int c1 = input.nextInt();
int d1 = input.nextInt();
int e1 = input.nextInt();
int ma1 = max(a1,b1,c1,d1,e1);
float a2 = input.nextFloat();
float b2 = input.nextFloat();
float c2 = input.nextFloat();
float d2 = input.nextFloat();
float e2 = input.nextFloat();
float ma2 = max(a2,b2,c2,d2,e2);
long a3 = input.nextLong();
long b3 = input.nextLong();
long c3 = input.nextLong();
long d3 = input.nextLong();
long e3 = input.nextLong();
long ma3 = max(a3,b3,c3,d3,e3);
System.out.println(ma1+"\n"+ma2+"\n"+ma3);
}
}
public class Main {
static int max(int a,int b,int c,int d,int e){
int max = a;
if(max < b) max = b;
if(max < c) max = c;
if(max < d) max = d;
if(max < e) max = e;
return max;
}
static long max(long a,long b,long c,long d,long e){
long max = a;
if(max < b) max = b;
if(max < c) max = c;
if(max < d) max = d;
if(max < e) max = e;
return max;
}
static float max(float a,float b,float c,float d,float e){
float max = a;
if(max < b) max = b;
if(max < c) max = c;
if(max < d) max = d;
if(max < e) max = e;
return max;
}
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int a1 = input.nextInt();
int b1 = input.nextInt();
int c1 = input.nextInt();
int d1 = input.nextInt();
int e1 = input.nextInt();
int ma1 = max(a1,b1,c1,d1,e1);
float a2 = input.nextFloat();
float b2 = input.nextFloat();
float c2 = input.nextFloat();
float d2 = input.nextFloat();
float e2 = input.nextFloat();
float ma2 = max(a2,b2,c2,d2,e2);
long a3 = input.nextLong();
long b3 = input.nextLong();
long c3 = input.nextLong();
long d3 = input.nextLong();
long e3 = input.nextLong();
long ma3 = max(a3,b3,c3,d3,e3);
System.out.println(ma1+"\n"+ma2+"\n"+ma3);
}
}
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