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python 聚类分析实战案例:K-means算法(原理源码)

2017-12-20 14:44 281 查看
K-means算法:



关于步骤:参考之前的博客

关于代码与数据:暂时整理代码如下:后期会附上github地址,上传原始数据与代码完整版,



各种聚类算法的对比:参考连接

Kmeans算法的缺陷

1.聚类中心的个数K 需要事先给定,但在实际中这个 K 值的选定是非常难以估计的,很多时候,事先并不知道给定的数据集应该分成多少个类别才最合适

2.Kmeans需要人为地确定初始聚类中心,不同的初始聚类中心可能导致完全不同的聚类结果。

#!usr/bin/env python
#_*_ coding:utf-8 _*_
import random
import math
'''
kMeans:2列数据对比,带有head
'''
#1.load data
def importData():
f = lambda name,b,d: [name, float(b), float(d)]

with open('birth-death-rates.csv', 'r') as inputFile:
return [f(*line.strip().split('\t')) for line in inputFile]


写入文件类型



#2. calculate Distance

def euclideanDistance(x,y):
return math.sqrt(sum([(a-b)**2 for (a,b) in zip(x,y)]))

#L=points,
def partition(points, k, means, d=euclideanDistance):
# print('means={}'.format(means))
thePartition = [[]
e368
for _ in means]  # list of k empty lists

indices = range(k)
# print('indices={}'.format(indices))

for x in points:

#index为indices索引,调用d函数,计算每个值与聚类中心的距离,将其分类
closestIndex = min(indices, key=lambda index: d(x, means[index]))#实现X与每个Y直接的求解:key=lambda index: d(x, means[index])

thePartition[closestIndex].append(x)

return thePartition




#3.寻找收敛点
def mean(points):
''' assume the entries of the list of points are tuples;
e.g. (3,4) or (6,3,1). '''

n = len(points)
# print(tuple(float(sum(x)) / n for x in zip(*points)))   #*points将【[1,2],[2,3]】分割出来【1,2】
return tuple(float(sum(x)) / n for x in zip(*points))  #将最开始的[[4, 1], [1, 5]] 经过处理变成[(4, 1),(1, 5)]

def kMeans(points, k, initialMeans, d=euclideanDistance):
oldPartition = []
newPartition = partition(points, k, initialMeans, d)

while oldPartition != newPartition:
oldPartition = newPartition
newMeans = [mean(S) for S in oldPartition]
newPartition = partition(points, k, newMeans, d)

return newPartition


#0.函数调用初始中心点

if __name__ == "__main__":
L = [x[1:] for x in importData()] # remove names
# print (str(L).replace('[','{').replace(']', '}'))
import matplotlib.pyplot as plt
'''
plt.scatter(*zip(*L))
plt.show()
'''
import random
k = 3
partition = kMeans(L, k, random.sample(L, k))  #L是集合,K分类个数,random.sample(L, k)中心点
plt.scatter(*zip(*partition[0]), c='b')#[[],[],[]]
plt.scatter(*zip(*partition[1]), c='r')
plt.scatter(*zip(*partition[2]), c='g')
plt.show()


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