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2017 ACM-ICPC ECL-FINAL 部分代码

2017-12-18 15:06 495 查看


以下代码均为现场代码,注释不存在的

A

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int mod=1e9+7;
ll power(ll n,ll p){
ll ans=1;
ll base=n;
while(p){
if(p&1){
ans=ans*base%mod;
}
base=base*base%mod;
p>>=1;
}
return ans;
}
ll inv(ll n){
return power(n,mod-2);
}
int main(){
int T;
scanf("%d",&T);
for(int tt=1;tt<=T;tt++){
ll n,k;
scanf("%lld%lld",&n,&k);
//cout<<power(2,6)<<endl;
ll sum=(power(2,n)-1+mod)%mod;
ll up=1,down=1;
//cout<<sum<<endl;
for(ll i=1;i<k&&i<=n;i++){
up=up*(n-i+1)%mod;
down=down*i%mod;
//cout<<up<<' '<<down<<endl;
sum=(sum-up*inv(down))%mod;
sum=(sum+mod)%mod;
}
printf("Case #%d: %lld\n",tt,sum);
}
}


B

#include<bits/stdc++.h>
using namespace std;
const int maxn = 200005;
double X;
struct P{
int sz,cnt;
double cc;
bool operator<(const P &p)const{
return cc < p.cc;
}
};
int A[maxn];
double cal(double a,double b){
return b * ((a / b - X ) * (a / b - X )) - (b + 1)*(a/(b+1) - X) * (a/(b+1) - X);
//return tmp * tmp;
}
priority_queue<P> que;
int main(){
//sint tmp = (1LL<<31)-1;
//cout<<tmp<<endl;
int T;
scanf("%d",&T);
int cs = 0;
while(T--){
int n,m;
scanf("%d%d",&n,&m);
while(!que.empty()) que.pop();
int sum = 0;
for(int i = 1;i<=n;i++){
scanf("%d",&A[i]);
sum += A[i];
}
X = sum * 1.0 / m;
for(int i = 1;i<=n;i++){
que.push((P){A[i],1,cal(A[i],1)});
}
for(int i = n+1;i<=m;i++){
P p = que.top();que.pop();
p.cnt++;
p.cc = cal(p.sz,p.cnt);
que.push(p);
}
double ans = 0;
while(!que.empty()){
P p = que.top();que.pop();
ans += 1.0 * p.cnt * (1.0 * p.sz/p.cnt - X) * (1.0 * p.sz/p.cnt - X);
}
printf("Case #%d: %.10lf\n",++cs,ans/m);
}
}


C

#include <bits/stdc++.h>
using namespace std;
int main(){
int T;
scanf("%d",&T);
for(int tt=1;tt<=T;tt++){
int n;
scanf("%d",&n);
double sum=0,tmp=0;
for(int i=1;i<=n+1;i++){
scanf("%lf",&tmp);
sum+=tmp;
}
double M=0;
for(int i=1;i<=n;i++){
double a,b;
scanf("%lf%lf",&a,&b);
M=max(M,b);
}
sum+=M;
printf("Case #%d: %.10f\n",tt,sum);
}
}


D

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll ans[2000005];
int tot=0;
// p fz, q fm
ll tt[105];
ll le[105];
inline ll getlen(ll x){
ll ret = 1;
while(x){
ret*=10;
x/=10;
}
return ret;
}
ll get(ll a,ll p,ll q,int len){
ll tmp=a;
ll x = a;
tt[0] = a;
le[0] = getlen(tt[0]);
for(ll i=1;i<len;i++){
if(tmp%q)return 1e15+1;
tmp /= q;
x /= q;
if(x > 1e15 / p) return 1e15+1;
x *= p;
tt[i] = x;
le[i] = getlen(tt[i]);
}
ll ret = 0;
for(int i = 0;i<len;i++){
//cout<<tt[i]<<' '<<le[i]<<endl;
if(ret > 1e15 / le[i]) return 1e15+1;
ret *= le[i];
ret += tt[i];
}
return ret;
}
bool flag = 0 ;
void solve(ll a,ll q){
for(ll p=q+1;;p++){
if(get(a,p,q,3)>1e15)break;
for(int j=3;;j++){
ll tmp=get(a,p,q,j);
if(tmp>1e15)break;
/*if(tmp < 0){
//cout<<a<<' '<<p<<' '<<q<<' '<<j<<endl;
//flag = 1;
//return;
}*/
ans[++tot]=tmp;
}
}
}

ll Ans[2000005];
int main(){

for(ll i=1;i<100000;i++){
for(ll j=1;j*j<=i;j++){
if(i%(j*j)==0){
solve(i,j);
//if(flag) return 0;
}
}
}
//cout<<get(1,1,2,4)<<endl;
//cout<<tot<<endl;
sort(ans+1,ans+tot+1);
//tot = unique(ans+1,ans+tot+1)-ans;
int tot1 = 0;
for(int i = 1;i<=tot;i++)
if(ans[i]!=ans[i-1])
Ans[++tot1] = ans[i];
//cout<<tot<<endl;
//cout<<tot1<<endl;
//for(int i = tot1;i>tot1-10;i--)
//  cout<<Ans[i]<<endl;
//cout<<get(1024,1,2,5);
//for(int i = 0;i<10;i++)
//  cout<<tt[i]<<endl;

int T;
scanf("%d",&T);
int cs = 0;
while(T--){
ll l,r;
scanf("%lld%lld",&l,&r);
int rr = upper_bound(Ans+1,Ans+tot1+1,r) - Ans - 1;
int ll = upper_bound(Ans+1,Ans+tot1+1,l-1) - Ans - 1;
printf("Case #%d: %d\n",++cs,rr-ll);
}
}


H

#include <bits/stdc++.h>
using namespace std;
char s[1000003];
char s1[1000003];
int dp[1000003][2];
int main(){
int T;
scanf("%d",&T);
for(int tt=1;tt<=T;tt++){
scanf("%s",s+1);
int a,b;
scanf("%d%d",&a,&b);
memset(dp,-1,sizeof(dp));
int n=strlen(s+1);
for(int i=1;i<=n;i++){
if(s[i]=='a'||s[i]=='e'||s[i]=='o'||s[i]=='i'||s[i]=='u')s[i]='0';
else if(s[i]!='?')s[i]='1';
}
dp[0][0]=dp[0][1]=0;
for(int i=1;i<=n;i++){
if(s[i]=='?'){
if(dp[i-1][1]!=-1){
dp[i][0]=1;
}
else if(dp[i-1][0]!=-1){
dp[i][0]=dp[i-1][0]+1;
}
if(dp[i][0]>=a)dp[i][0]=-1;

if(dp[i-1][0]!=-1){
dp[i][1]=1;
}
else if(dp[i-1][1]!=-1){
dp[i][1]=dp[i-1][1]+1;
}
if(dp[i][1]>=b)dp[i][1]=-1;
}
else if(s[i]=='0'){
if(dp[i-1][1]!=-1){
dp[i][0]=1;
}
else if(dp[i-1][0]!=-1){
dp[i][0]=dp[i-1][0]+1;
}
if(dp[i][0]>=a)dp[i][0]=-1;
}
else {
if(dp[i-1][0]!=-1){
dp[i][1]=1;
}
else if(dp[i-1][1]!=-1){
dp[i][1]=dp
dcc0
[i-1][1]+1;
}
if(dp[i][1]>=b)dp[i][1]=-1;
}
}
bool tag1=false;
if(dp
[0]!=-1||dp
[1]!=-1)tag1=true;
bool tag2=false;
int tmp=0;
//cout<<s+1<<endl;
for(int i=1;i<=n;i++){
if(s[i]=='?')s1[i]='0';
else s1[i]=s[i];
if(s1[i]=='0')tmp++;
else {
tmp=0;
}
if(tmp>=a)tag2=true;
}
tmp=0;
for(int i=1;i<=n;i++){
if(s[i]=='?')s1[i]='1';
else s1[i]=s[i];
if(s1[i]=='1')tmp++;
else {
tmp=0;
}
if(tmp>=b)tag2=true;
}
//cout<<tag1<<' '<<tag2<<endl;
if(tag1&&tag2)printf("Case #%d: SURPRISE\n",tt);
else if(tag1){
printf("Case #%d: LIKE\n",tt);
}
else if(tag2){
printf("Case #%d: DISLIKE\n",tt);
}
}
}


J

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
deque<ll>dq;
ll a[200003];
int main(){
int T;
scanf("%d",&T);
for(int tt=1;tt<=T;tt++){
int n;
scanf("%d",&n);
while(!dq.empty())dq.pop_back();
bool flag=true;
ll k=0;
for(int i=1;i<=n;i++){
scanf("%lld",&a[i]);
}
a[++n]=0;
for(int i=1;i<=n;i++){
if(dq.empty()){
dq.push_back(a[i]);
continue;
}
while(k+a[i]<dq.back()){
if(dq.size()<=2){
flag=false;
break;
}
if(dq.front()+a[i]<dq.back()){
k=dq.front();
}
else {
k=dq.back()-a[i];
}
while(!dq.empty()&&dq.front()==k)dq.pop_front();
}
if(!flag)break;
dq.push_back(k+a[i]);
if(a[i]==0){
while(!dq.empty())dq.pop_back();
k=0;
}
//cout<<k<<endl;
}
if(!flag)printf("Case #%d: No\n",tt);
else printf("Case #%d: Yes\n",tt);
}
}


K

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll l[105000];
ll pre[105000];
int main(){
int T;
scanf("%d",&T);
for(int tt=1;tt<=T;tt++){
ll A,b,n,a;
scanf("%lld%lld%lld",&a,&b,&n);
A=a;
for(int i=1;i<=A;i++){
scanf("%lld",&l[i]);
pre[i]=pre[i-1]+l[i];
}
for(int i=1;i<=n;i++){
ll pos=lower_bound(pre+1,pre+1+A,a)-pre;
ll ap=pos;
ll bp=a-pre[pos-1];
//cout<<a<<' '<<b<<endl;
if(ap==a&&bp==b)break;
a=ap,b=bp;
}
printf("Case #%d: %lld-%lld\n",tt,a,b);
}
}


L的代码找不到了,结论是大于等于7的奇数先手赢,大于等于16的偶数后手赢,其余平。

M

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll p[5];
ll v[5];
int main(){
int T;
scanf("%d",&T);
for(int tt=1;tt<=T;tt++){
for(int i=0;i<5;i++)scanf("%lld",&v[i]);
p[0]=48;
p[1]=p[0]+8;
p[2]=p[1]+4;
p[3]=p[2]+2;
p[4]=p[3]+1;
int num;
scanf("%d",&num);
ll ans=0;
for(int i=1;i<=num;i++){
int id;
scanf("%d",&id);
for(int j=0;j<5;j++){
if(id<=p[j]){
ans+=v[j];
break;
}
}
}
printf("Case #%d: %lld\n",tt,ans*10000);
}
}
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