Lintcode166 Nth to Last Node in List solution 题解
2017-11-30 15:07
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【题目描述】
Find the nth to last element of a singly linked list.
The minimum number of nodes in list is n.
找到单链表倒数第n个节点，保证链表中节点的最少数量为n。
【题目链接】
www.lintcode.com/en/problem/nth-to-last-node-in-list/
【题目解析】
这一道找倒数第n个结点的链表题，可用双指针做。
由于链表没有得到长度的值，只能通过一个一个移来进行判断
可fast先走n，然后fast和slow一起走，直到fast为null，slow的位置就是倒数第n个位置。
【参考答案】
www.jiuzhang.com/solutions/nth-to-last-node-in-list/
Find the nth to last element of a singly linked list.
The minimum number of nodes in list is n.
找到单链表倒数第n个节点，保证链表中节点的最少数量为n。
【题目链接】
www.lintcode.com/en/problem/nth-to-last-node-in-list/
【题目解析】
这一道找倒数第n个结点的链表题，可用双指针做。
由于链表没有得到长度的值，只能通过一个一个移来进行判断
可fast先走n，然后fast和slow一起走，直到fast为null，slow的位置就是倒数第n个位置。
【参考答案】
www.jiuzhang.com/solutions/nth-to-last-node-in-list/
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