编程实现：两个int（32位）整数m和n的二进制表达中，有多少个位(bit)不同？

#include<stdio.h>
#include<windows.h>
int compare_bit(int x, int y)
{
int i = 0;
int count = 0;
x ^= y;
for (i = 0; i < 32; i++)
{
if ((x >> i) & 1 == 1)
{
count++;
}
}
return count;
}
int main()
{
int a = 1999;
int b = 2999;
printf("%d和%d二进制bit位中有%d个比特位不同\n",a,b,compare_bit(a,b));
system("pause");
return 0;
}