LintCode-【容易】9.Fizz Buzz问题

fizz

buzz

3

5

fizz
buzz

15

[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]

C/C++： vector<string> 加两个标志变量搞定

class Solution {
public:
/*
* @param n: An integer
* @return: A list of strings.
*/
vector<string> fizzBuzz(int n)
{
// write your code here
vector<string> fb;
int count = 0;
for (int i = 1; i <= n; i++)
{
bool Index3 = false, Index5 = false;
if (i % 3 == 0)  Index3 = true;
if (i % 5 == 0)  Index5 = true;

if (!Index3&&!Index5)         fb.push_back(to_string(i));
else if (Index3&&!Index5)     fb.push_back("fizz");
else if (!Index3&&Index5)     fb.push_back("buzz");
else                          fb.push_back("fizz buzz");

}
return fb;

}
};

2.python:  注意数组的初始化

class Solution:
"""
@param n: An integer as description
@return: A list of strings.

"""
def fizzBuzz(self, n):
results = []
for i in range(1, n+1):
if i % 15 == 0:
results.append("fizz buzz")
elif i % 5 == 0:
results.append("buzz")
elif i % 3 == 0:
results.append("fizz")
else:
results.append(str(i))
return results

ArrayList<String>

public class Solution {    /*     * @param n: An integer     * @return: A list of strings.     */    public List<String> fizzBuzz(int n) {        // write your code here       ArrayList<String> results = newArrayList<String>();        for (int i = 1; i <= n; i++) {            if (i % 15 == 0) {                results.add("fizz buzz");            } else if (i % 5 == 0) {                results.add("buzz");            } else if (i % 3 == 0) {                results.add("fizz");            } else {                results.add(String.valueOf(i));            }        }        return results;    }}有关Java：ArrayList用法，可以看看：https://www.cnblogs.com/bayes/p/5474728.html