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java 单链表简单实现

2017-11-05 15:54 211 查看
为了方便学习写的简单的链表,方便学习算法与数据结构的同学。

不多解释,直接看代码:

public class Link_List<T> {

private node head = null;
private node end = null;
private int size;

private class node{
public T value;//值
node next = null;//下一个节点
public node() {

}
public node(T value) {
this.value = value;
}
@Override
public String toString() {
return this.value.toString();
}
public boolean equals(node nod) {
if(this.value.equals(nod.value)) {
return true;
}
return false;
}
}
//构造方法
public Link_List(T[] arr) {
this.size = arr.length;
head = new node();
node nod = head;
for(int i = 0; i < arr.length ; i++) {
nod.value = arr[i];
nod.next = new node();
end = nod;//更新末尾节点,待优化
nod = nod.next;
}
}
public Link_List(T value) {
head = new node();
head.value = value;
size = 1;
end = head;
}
public Link_List() {

}

private node findNode(int index) {
node nod = head;
for(int i = 0 ; i < index ; i++ ) {
nod = nod.next;
}
return nod;
}

public void add(T value) {
node nod = findNode(size-1);
nod.next = new node(value);
end = nod.next;
size++;
}
public void add(T value , int index) {
if(index == size-1) {
add(value);
}else if(index == 0){
node nod = new node(value);
nod.next = head;
head = nod;
size++;
}else {
node preNode = findNode(index - 1);
node nextNode = findNode(index);
node nod = new node(value);
preNode.next = nod;
nod.next = nextNode;
size++ ;
}
}

public void delete(int index) {
if(index == size-1) {
end = null;
end = findNode(index-1);
size--;
}else if(index == 0){
head = head.next;
size--;
}else {
node preNode = findNode(index - 1);
node nextNode = findNode(index + 1);
preNode.next = nextNode;
findNode(index).next = null;//释放持有的引用
size--;
}
}

public T get(int index) {
node nod = findNode(index);
return nod.value;
}

@Override
public String toString() {
node nod = head;
String res = head.toString() ;
for(int i = 0 ; i < size ; i++) {
nod = nod.next;
if(nod != null) {
res += " >> " + nod.value;
}else {
res += " >> null";
}
}
return res;
}

public void reverse() {
node nod = head;
node pre = new node();
while(nod != null){
node next = nod.next;
nod.next = pre;
pre = nod;
nod = next;
}
end = head;
head = pre;
}
}


测试:

public static void main(String[] args) {
//test:
Integer[] test = new Integer[] {0,1,2,3,4,5,6,7,8,9};
Link_List<Integer> mLink_List = new Link_List<Integer>(test);
System.out.println(mLink_List);
mLink_List.delete(2);
mLink_List.add(666,2);
System.out.println(mLink_List.get(2));
System.out.println(mLink_List);
}


结果:

Console:

0 >> 1 >> 2 >> 3 >> 4 >> 5 >> 6 >> 7 >> 8 >> 9 >> null
666
0 >> 1 >> 666 >> 3 >> 4 >> 5 >> 6 >> 7 >> 8 >> 9 >> null
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