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线程基础之挂起与通知

2017-10-01 00:00 155 查看
public class NotifyAndWaitTest extends Thread {
private Integer num = 0;
private static Boolean lock = false;

private void addNum() {
num++;
}

private void soutNum() {
System.out.println(Thread.currentThread().getName() + " : "
+ num);
}

public static void main(String[] args) {
NotifyAndWaitTest notifyAndWaitTest = new NotifyAndWaitTest();

Thread t1 = new Thread(new Runnable() {
@Override
public void run() {
synchronized (lock) {
for (int i = 0; i < 5; i++) {
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
if (i == 2) {

lock.notify();// t1通知t2继续执行

System.out.println(Thread.currentThread().getName() + " : "
+ "通知发出,t2将继续执行");
}
notifyAndWaitTest.addNum();
notifyAndWaitTest.soutNum();
}
try {

lock.wait();// t1挂起

System.out.println(Thread.currentThread().getName() + " : "
+ "线程准备开始执行");
} catch (InterruptedException e) {
e.printStackTrace();
}
}
System.out.println(Thread.currentThread().getName() + " : "
+ "执行完毕");
}
}, "t1");

Thread t2 = new Thread(new Runnable() {
@Override
public void run() {
synchronized (lock) {
try {
lock.wait();// t2开始挂起
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println(Thread.currentThread().getName() + " : "
+ "收到通知开始");

lock.notify();// t2通知t1继续执行

System.out.println(Thread.currentThread().getName() + " : "
+ "通知发出,t1将继续执行");
System.out.println(Thread.currentThread().getName() + " : "
+ "执行完毕");
}
}
}, "t2");

t2.start();
try {
Thread.sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
t1.start();
}
}

t1 : 1
t1 : 2
t1 : 通知发出,t2将继续执行
t1 : 3
t1 : 4
t1 : 5
t2 : 收到通知开始
t2 : 通知发出,t1将继续执行
t2 : 执行完毕
t1 : 线程准备开始执行
t1 : 执行完毕

从这里可以看出,挂起时,线程将释放锁。
而通知时,并不会释放锁。
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标签:  java