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java-源码解读-线程池提交之execute和submit有何不同

2017-09-28 14:42 791 查看

先上测试用例

package com.phl.threadpool;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

/**
* @Title:SubmitExecuteMain
* @Description:
* @Copyright:中国电信爱wifi运营中心
* @author:panhl
* @date 2017/9/26 0026 10:34
*/
public class SubmitExecuteMain {
public static void main(String[] args) throws Exception{
submit();
submitWithGet();
execute();
}
private static void submitWithGet() throws Exception{
ExecutorService service= Executors.newSingleThreadExecutor();
Future future=service.submit(new Runnable() {
@Override
public void run() {
int i=7/0;
}
});
    service.shutdown();
future.get();
}
private static void submit(){ ExecutorService service= Executors.newSingleThreadExecutor(); service.submit(new Runnable() { @Override public void run() { int i=7/0; } }); service.shutdown(); } private static void execute(){ ExecutorService service= Executors.newSingleThreadExecutor(); service.execute(new Runnable() { @Override public void run() { int i=7/0; } }); service.shutdown(); }}

先下结论

1.对返回值的处理不同
execute方法不关心返回值。
submit方法有返回值,Future。
2.对异常的处理不同
excute方法会抛出异常。
sumbit方法不会抛出异常。除非你调用Future.get()。

再看原理

当我们调用ExecutorService的submit的时候,其实是调用了
AbstractExecutorService.submit方法。直接看源码:
public Future<?> submit(Runnable task) {
if (task == null) throw new NullPointerException();
RunnableFuture<Void> ftask = newTaskFor(task, null);
execute(ftask);
return ftask;
}
 从上面的代码可以看出 execute和sumbit方法的不同在于这一行封装:
RunnableFuture<Void> ftask = newTaskFor(task, null);
 这就是关键所在。

 先看execute方法

 当我们调用execute时,以ThreadPoolExecutor实现为例,他就是调用了ThreadPoolExecutor的execute方法。
public void execute(Runnable command) {
if (command == null)
throw new NullPointerException();
int c = ctl.get();
if (workerCountOf(c) < corePoolSize) {
if (addWorker(command, true))
return;
c = ctl.get();
}
if (isRunning(c) && workQueue.offer(command)) {
int recheck = ctl.get();
if (! isRunning(recheck) && remove(command))
reject(command);
else if (workerCountOf(recheck) == 0)
addWorker(null, false);
}
else if (!addWorker(command, false))
reject(command);
} 
这里不分析 execute方法内部实现,我想说的是ExecutorService的execute方法提交的任务被原模原样的的转交给了实现类ThreadPoolExecutor的execute方法。
也就是说原来提交的是Runnable,执行的也是Runnable.
具体提交任务流程不在这里作分析,最后直接看任务的执行代码:ThreadPoolExecutor.runWorker final void runWorker(Worker w) {
Thread wt = Thread.currentThread();
Runnable task = w.firstTask;
w.firstTask = null;
w.unlock(); // allow interrupts
boolean completedAbruptly = true;
try {
while (task != null || (task = getTask()) != null) {
w.lock();
if ((runStateAtLeast(ctl.get(), STOP) ||
(Thread.interrupted() &&
runStateAtLeast(ctl.get(), STOP))) &&
!wt.isInterrupted())
wt.interrupt();
try {
beforeExecute(wt, task);
Throwable thrown = null;
try {
task.run();
} catch (RuntimeException x) {
thrown = x; throw x;
} catch (Error x) {
thrown = x; throw x;
} catch (Throwable x) {
thrown = x; throw new Error(x);
} finally {
afterExecute(task, thrown);
}
} finally {
task = null;
w.completedTasks++;
w.unlock();
}
}
completedAbruptly = false;
} finally {
processWorkerExit(w, completedAbruptly);
}
}真正执行的地方在task.run这一行,task 就是原模原样提交的Runnable,也就是执行了Runnable.run方法。有异常就抛异常

再看sumbit方法

sumbit方法的不同之处在于上面提到的那一行,对Runnable的封装。RunnableFuture<Void> ftask = newTaskFor(task, null);直接看newTaskFor方法把 Runnable封装成了什么东西:
protected <T> RunnableFuture<T> newTaskFor(Runnable runnable, T value) {
return new FutureTask<T>(runnable, value);
}
public FutureTask(Runnable runnable, V result) {
this.callable = Executors.callable(runnable, result);
this.state = NEW;       // ensure visibility of callable
}
Runnable转变过程:
Runnable-----newTaskFor----->new FutureTask()------->FutureTask
任务的转变过程:
Runnable.run()-----Executors.callable(runnable, result)------->Callable.call()
通过上面两个方法,Runnable已经转变成了FutureTask。
关于FutureTask ,请参考我的另一篇博客:java-源码解读-FutureTask 

通过上面对execute方法的分析,我们知道runWorker 方法中那句task.run()其实也就是FutureTask.run()了。
直接看FutureTask.run()都干了什么:
public void run() {
if (state != NEW ||
!UNSAFE.compareAndSwapObject(this, runnerOffset,
null, Thread.currentThread()))
return;
try {
Callable<V> c = callable;
if (c != null && state == NEW) {
V result;
boolean ran;
try {
result = c.call();
ran = true;
} catch (Throwable ex) {
result = null;
ran = false;
setException(ex);
}
if (ran)
set(result);
}
} finally {
runner = null;
int s = state;
if (s >= INTERRUPTING)
handlePossibleCancellationInterrupt(s);
}
}
代码很清楚,run方法中真正执行任务的地方为c.call(),也就是调用Callable.call(),当c.call()发生异常时 catch了,并调用了setExcetion方法:
protected void setException(Throwable t) {
if (UNSAFE.compareAndSwapInt(this, stateOffset, NEW, COMPLETING)) {
outcome = t;
UNSAFE.putOrderedInt(this, stateOffset, EXCEPTIONAL); // final state
finishCompletion();
}
}
setException把抛出的异常赋值给了outcome,outcome就是Futer.get() 的返回结果。
所以就有了开始的结论,submit提交任务时不会有异常,因为异常被当作结果返回了。
要想submit方法也抛出异常,可以调用 Future.get(); Future的get 方法如下: public V get() throws InterruptedException, ExecutionException {
int s = state;
if (s <= COMPLETING)
s = awaitDone(false, 0L);
return report(s);
}
private V report(int s) throws ExecutionException {
Object x = outcome;
if (s == NORMAL)
return (V)x;
if (s >= CANCELLED)
throw new CancellationException();
throw new ExecutionException((Throwable)x);
}
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