您的位置:首页 > 编程语言 > C语言/C++

C语言 数据类型占多少字节,指针占多少字节

2017-09-26 21:20 246 查看
#include<stdio.h>
void main()
{
//使用sizeof验证数据类型在内存中占用的空间大小
//    char
//    int
//    short
//    long
//    unsigned int
//    float
//    double
//    long double
printf("在64位机器中:\n");
printf("        char类型占%d个字节\n",sizeof(char));
printf("       short类型占%d个字节\n",sizeof(short));
printf("         int类型占%d个字节\n",sizeof(int));
printf("        long类型占%d个字节\n",sizeof(long));
printf("unsigned int类型占%d个字节\n",sizeof(unsigned int));
printf("       float类型占%d个字节\n",sizeof(float));
printf("      double类型占%d个字节\n",sizeof(double));
printf(" long double类型占%d个字节\n",sizeof(long double));
printf("-------------------指针占4个字节---------------------\n");
char *p0;
short *p1;
int *p2;
long *p3;
unsigned int *p4;
float *p5;
double *p6;
long double *p7;
printf("        char类型指针占%d个字节\n",sizeof(p0));
printf("       short类型指针占%d个字节\n",sizeof(p1));
printf("         int类型指针占%d个字节\n",sizeof(p2));
printf("        long类型指针占%d个字节\n",sizeof(p3));
printf("unsigned int类型指针占%d个字节\n",sizeof(p4));
printf("       float类型指针占%d个字节\n",sizeof(p5));
printf("      double类型指针占%d个字节\n",sizeof(p6));
printf(" long double类型指针占%d个字节\n",sizeof(p7));
}

结果:

在64位机器中:
char类型占1个字节
short类型占2个字节
int类型占4个字节
long类型占4个字节
unsigned int类型占4个字节
float类型占4个字节
double类型占8个字节
long double类型占12个字节
-------------------指针占4个字节---------------------
char类型指针占4个字节
short类型指针占4个字节
int类型指针占4个字节
long类型指针占4个字节
unsigned int类型指针占4个字节
float类型指针占4个字节
double类型指针占4个字节
long double类型指针占4个字节
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: