LeetCode 7. Reverse Integer C++--带正负号数字反转
2017-08-09 10:29
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Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
click to show spoilers.
Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
#include <iostream>
using namespace std;
int reverse(int x){
long res = 0;
while(x){
res = res*10 + x%10;
x = x/10;
}
return (res >INT_MAX || res <INT_MIN)?0:res;
}
int main(){
cout<<reverse(-123)<<endl;
return 0;
}
1032 / 1032 test cases passed.
Status: Accepted
Runtime: 22 ms
Your runtime beats 30.40 % of cpp submissions
Example1: x = 123, return 321
Example2: x = -123, return -321
click to show spoilers.
Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
#include <iostream>
using namespace std;
int reverse(int x){
long res = 0;
while(x){
res = res*10 + x%10;
x = x/10;
}
return (res >INT_MAX || res <INT_MIN)?0:res;
}
int main(){
cout<<reverse(-123)<<endl;
return 0;
}
1032 / 1032 test cases passed.
Status: Accepted
Runtime: 22 ms
Your runtime beats 30.40 % of cpp submissions
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