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leetcode 24. Swap Nodes in Pairs

2017-07-16 21:31 375 查看
Given a linked list, swap every two adjacent nodes and return its head.

For example,

Given
1->2->3->4
, you should return the list as
2->1->4->3
.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

解:迭代的思想

/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
if(head){
if(head->next){
ListNode* tmp = head->next;
head->next = swapPairs(tmp->next);
tmp->next = head;
return tmp;
}else return head;
}else return head;
}
};
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标签:  leetcode 算法