C++实现字符串中数字字串求和

#include <iostream>

using namespace std;

int strToNumber(string str){
if (str.length()==0)
return 0;
int count = 0;
int sum ;
bool flag;//标记正负取值，flag为true则为正，false为负
int i = 0;
while (i<str.length())//循环遍历每一个字符
{
flag = true;
sum = 0;
while (i<str.length()&&str[i]=='-'){//统计-的个数
flag = !flag;
i++;
}
while (i<str.length()&&str[i] >= '0'&&str[i] <= '9')//遍历到数字时，进行累加计算子数字串
{
sum = sum * 10 + (str[i] - '0');
i++;
}
sum = flag ? sum : -sum;
count += sum;//统计子数字串和
i++;

}
return count;
}

int main(){
string str1 = "A1CD2E33";
string str2 = "A-1B--2C--D6E";
int result1=strToNumber(str1);
int result2 = strToNumber(str2);
cout << result1 << endl<<result2<<endl;
cin.get();
return 0;
}