您的位置:首页 > Web前端 > Node.js

LeetCode——237. Delete Node in a Linked List

2017-06-28 00:50 323 查看

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

/**
* Definition for singly-linked list.
* public class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) { val = x; }
* }
*/
public class Solution {
public void deleteNode(ListNode node) {
ListNode next = node.next;
int temp = node.val;
node.val = next.val;
next.val = temp;
node.next = next.next;
}
}


简单的算法不要忽略细节和算法边界值、特殊值的判断。

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  leetcode 函数