给定一个字符串，你需要颠倒一个句子中每个单词中的字符顺序，同时保留空格和初始单词顺序。

public static void main(String[] args) {
String str = "we are family's";
StringBuffer sb = new StringBuffer(str).reverse();
String[] split = sb.toString().split(" ");
sb = new StringBuffer();
for (int i = 0;i<split.length;i++){
sb.append(split[split.length-1-i]).append(" ");
}
System.out.println(sb.toString());
}

public class Solution {
public String reverseWords(String s) {
String words[] = s.split(" ");
StringBuilder res=new StringBuilder();
for (String word: words)
res.append(new StringBuffer(word).reverse().toString() + " ");
return res.toString().trim();
}
}

public class Solution {
public String reverseWords(String s) {
String words[] = split(s);
StringBuilder res=new StringBuilder();
for (String word: words)
res.append(reverse(word) + " ");
return res.toString().trim();
}
public String[] split(String s) {
ArrayList < String > words = new ArrayList < > ();
StringBuilder word = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) == ' ') {
words.add(word.toString());
word = new StringBuilder();
} else
word.append( s.charAt(i));
}
words.add(word.toString());
return words.toArray(new String[words.size()]);
}
public String reverse(String s) {
StringBuilder res=new StringBuilder();
for (int i = 0; i < s.length(); i++)
res.insert(0,s.charAt(i));
return res.toString();
}
}