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Java 遍历Map时 删除元素ZZ

2017-06-23 00:00 387 查看
http://niewj.iteye.com/blog/1469161

package net.nie.test;

import java.util.HashMap;

import java.util.Iterator;

import java.util.Map;

public class HashMapTest {

private static Map map=new HashMap();

public static void main(String[] args) {

map.put(1,"one");

map.put(2,"two");

map.put(3,"three");

map.put(4,"four");

map.put(5,"five");

map.put(6,"six");

map.put(7,"seven");

map.put(8,"eight");

map.put(5,"five");

map.put(9,"nine");

map.put(10,"ten");

Iterator> it = map.entrySet().iterator();

while(it.hasNext()){

Map.Entry entry=it.next();

int key=entry.getKey();

if(key%2==1){

System.out.println("delete this: "+key+" = "+key);

//map.put(key, "奇数"); //ConcurrentModificationEx ception

//map.remove(key); //ConcurrentModificationEx ception

it.remove(); //OK

}

}

//遍历当前的map;这种新的for循环无法修改map内容,因为不通过迭代器。

System.out.println("-------\n\t最终的map的元素遍历:");

for(Map.Entry entry:map.entrySet()){

int k=entry.getKey();

String v=entry.getValue();

System.out.println(k+" = "+v);

}

}

}
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