hive sql解决关联条件中不等值连接问题及累计值的计算

工作中写的sql，本次的sql可以拓展出一些新内容，留下笔记

with a as (
select
interface
,case when action is NUll then 'null' else action end as action
, request_time*1000 as request_time
,count(request_time) as pv
from
xx_xx
where ds >= %YYYYMMDD% || '00'
and ds <= %YYYYMMDD% || '23'
group by
interface
,action
,request_time * 1000
),

b as (
select
a1.interface
,a1.action
,a1.request_time
,a1.pv
,sum(case when a1.request_time>= a2.request_time then a2.pv end) as sum_cnt --解决hive sql关联条件中不等值连接问题
from
a a1
join a a2
on
a1.interface = a2.interface
and
a1.action = a2.action
group by
a1.interface
,a1.action
,a1.request_time
,a1.pv
),

c as (
select
b.interface
,b.action
,case when b.sum_cnt / t.total_pv >=0.90 then b.request_time end as geo_time_90
,case when b.sum_cnt / t.total_pv >=0.95 then b.request_time end as geo_time_95
,case when b.sum_cnt / t.total_pv >=0.99 then b.request_time end as geo_time_99
from
b
join
(
select interface
,action
,sum(pv) as total_pv
from
a
group by
interface
,action
)t
on
b.interface = t.interface
and b.action = t.action
)
select
c.interface
,c.action
,min(geo_time_90) as geo_time_90
,min(geo_time_95) as geo_time_95
,min(geo_time_99) as geo_time_99
from
c
group by
c.interface
,c.action