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go-map的并发问题

2017-05-08 22:00 387 查看
go 语言的map是引用传递的、如果多个goroutine同时读写,必然导致冲突,所以一般我们在并发操作map的时候,一定要加锁,但是如果map里的value是还是map,那么并发操作这个value- map是不是也一样回引起冲突呢?答案是:是的,go里所有map的并发操作都需要加锁,这样才不会引起冲突,见如下代码。我对map td操作加了锁,对得到的value-map进行了写操作,没有加锁,通过go run -race aa.go 依然可以检测到冲突,所以结论就是:并发读写操作go语言的任何一个map都需要加锁,这样才能防止冲突。

// filename: aa.go
import (
"fmt"
"sync"
"time"
)

func main() {
td := map[string]map[string]int{"info": {"age": 10}}
var Lock sync.Mutex
for i := 0; i < 2; i++ {
go func(md map[string]map[string]int) {
Lock.Lock()
info := td["info"]
Lock.Unlock()
info["age"] = 100
fmt.Println("info:", info["age"])
}(td)
}
time.Sleep(1 * time.Second)
}


go 自带竞争检测机制调用如下命令

go run -race aa.go


结果如下:

info: 100
==================
WARNING: DATA RACE
Write at 0x00c4200162a0 by goroutine 6:
runtime.mapassign()      /home/liuguirong/golang/go/src/runtime/hashmap.go:485 +0x0
main.main.func1()
/home/liuguirong/lgr/getiplib/src/aa.go:17 +0xef
Previous write at 0x00c4200162a0 by goroutine 7:
runtime.mapassign()     /home/liuguirong/golang/go/src/runtime/hashmap.go:485 +0x0
main.main.func1()
/home/liuguirong/lgr/getiplib/src/aa.go:17 +0xef
Goroutine 6 (running) created at:
main.main()
/home/liuguirong/lgr/getiplib/src/aa.go:19 +0x1eb

Goroutine 7 (finished) created at:
main.main()
/home/liuguirong/lgr/getiplib/src/aa.go:19 +0x1eb
==================
==================
WARNING: DATA RACE
Write at 0x00c42005c3c8 by goroutine 6:
main.main.func1()
/home/liuguirong/lgr/getiplib/src/aa.go:17 +0x105

Previous write at 0x00c42005c3c8 by goroutine 7:
main.main.func1()
/home/liuguirong/lgr/getiplib/src/aa.go:17 +0x105

Goroutine 6 (running) created at:
main.main()
/home/liuguirong/lgr/getiplib/src/aa.go:19 +0x1eb

Goroutine 7 (finished) created at:
main.main()
/home/liuguirong/lgr/getiplib/src/aa.go:19 +0x1eb
==================
info: 100
Found 2 data race(s)
exit status 66
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标签:  并发 go map 竞争 冲突