HDOJ 1241 油田 DFS初级算法 java代码实现 详细注释
2017-04-22 00:49
465 查看
初级的DFS算法:
题目链接:点击打开链接
基本解题思路:就是往油田的上、下、左、右、左上、左下,右上、右下八个方向遍历
Total Submission(s): 30130 Accepted Submission(s): 17424
[/b]
[align=left]Problem Description[/align]
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots.
It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil. A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large
and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.
[align=left]Input[/align]
The input file contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100
and 1 <= n <= 100. Following this are m lines of n characters each (not counting the end-of-line characters). Each character corresponds to one plot, and is either `*', representing the absence of oil, or `@', representing an oil pocket.
[align=left]Output[/align]
For each grid, output the number of distinct oil deposits. Two different pockets are part of the same oil deposit if they are adjacent horizontally, vertically, or diagonally. An oil deposit will not contain more than 100 pockets.
[align=left]Sample Input[/align]
1 1
*
3 5
*@*@*
**@**
*@*@*
1 8
@@****@*
5 5
****@
*@@*@
*@**@
@@@*@
@@**@
0 0
[align=left]Sample Output[/align]
0
1
2
2
附:BFS 队列和循环队列 代码: 点击打开链接
题目链接:点击打开链接
基本解题思路:就是往油田的上、下、左、右、左上、左下,右上、右下八个方向遍历
Oil Deposits
[b]Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 30130 Accepted Submission(s): 17424
[/b]
[align=left]Problem Description[/align]
The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots.
It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil. A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large
and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.
[align=left]Input[/align]
The input file contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100
and 1 <= n <= 100. Following this are m lines of n characters each (not counting the end-of-line characters). Each character corresponds to one plot, and is either `*', representing the absence of oil, or `@', representing an oil pocket.
[align=left]Output[/align]
For each grid, output the number of distinct oil deposits. Two different pockets are part of the same oil deposit if they are adjacent horizontally, vertically, or diagonally. An oil deposit will not contain more than 100 pockets.
[align=left]Sample Input[/align]
1 1
*
3 5
*@*@*
**@**
*@*@*
1 8
@@****@*
5 5
****@
*@@*@
*@**@
@@@*@
@@**@
0 0
[align=left]Sample Output[/align]
0
1
2
2
import java.util.*; class Main{ public static void main(String args[]){ Scanner sc=new Scanner(System.in); while(sc.hasNext()){ int n=sc.nextInt(); int m=sc.nextInt(); if(n==0&&m==0){ break; } char a[][]=new char [m]; //字符数组装油田和* boolean vis[][]=new boolean [m]; //标记数组,说明该位置是否被用过 for(int i=0;i<n;i++){ String str=sc.next(); a[i]=str.toCharArray(); } for(int i=0;i<n;i++){ for(int j=0;j<m;j++){ vis[i][j]=true; //初始化标记数组,为true说明没被用过 } } int count=0; //油田数量 for(int i=0;i<n;i++){ for(int j=0;j<m;j++){ if(a[i][j]=='@'&&vis[i][j]){ //如果这个位置是油田,且没用被用过 vis[i][j]=false; //标记这个位置被用过 dfs(a,vis,i,j,n,m); //从这个位置开始搜索 count++; } } } System.out.println(count); } } public static void dfs(char a[][],boolean vis[][],int x,int y,int n,int m){ int t[][]={{-1,-1},{-1,0},{-1,1},{0,-1},{0,1},{1,-1},{1,0},{1,1}}; //上下左右,左上左下,右上右下,八个方向 for(int i=0;i<8;i++){ int nx=x+t[i][0]; //遍历该位置的八个方向 int ny=y+t[i][1]; if(nx>=0&&nx<n&&ny>=0&&ny<m){ //当新的位置还在范围内时,不会越界 if(a[nx][ny]=='@'&&vis[nx][ny]){ //如果还是油田,则接着搜索该位置的八个方向,并标记此位置已经被用过 vis[nx][ny]=false; dfs(a,vis,nx,ny,n,m); } } } } }
附:BFS 队列和循环队列 代码: 点击打开链接
相关文章推荐
- PageRank的Java代码实现及图形操作(带详细注释)!
- 插入排序及归并排序java代码实现及详细注释
- PHP 图片上传实现代码 带详细注释
- PHP和Ajax实现二级联动下拉菜单(代码、详细注释)
- Java实现链表结构的详细代码
- Objective-C 【电商APP应用代码-系统分析-详细注释-代码实现】
- PHP 缓存实现代码及详细注释
- JAVA实现简单系统登陆注册模块的设计(附详细代码分析)
- 安卓开发20:动画之Animation 详细使用-主要通过java代码实现动画效果
- KNN算法java实现代码注释
- java实现链表结构详细代码
- JAVA连接Oracle数据库实代码+详细注释
- 根据Merge Sort原理, 自己实现的归并排序算法+详细注释+代码(C#,C/C++) [分享]
- 堆排序 完整代码与详细注释 C++语言实现
- 新浪微博自动转发评论 源码 按键精灵实现 详细注释 几十行代码实现 涉及图像识别模拟键盘鼠标
- KMP的原理和代码实现(详细注释|参考多个博客总结|可作为模板)
- 彩色图像直方图均衡化及颜色直方图显示 opencv实现 完整代码及详细注释
- 彩色图像直方图均衡化及颜色直方图显示 opencv实现 完整代码及详细注释
- 实现抽取java中的注释的代码
- Objective-C 【电商APP应用代码-系统分析-详细注释-代码实现】