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java 线程上机题 循环唤醒 三个线程轮流打印 顺序 A线程->B线程->C线程

2017-04-10 20:42 411 查看
package cn.itcast.mybatis.dao;

import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

/**
* 三个线程轮流打印 顺序    A线程->B线程->C线程
* A线程打印5次
* B线程打印10次
* C线程打印5次
* 以上规则运行20轮
* @author zhangkun
*
*/
class ShareSoucre{
Lock lock = new ReentrantLock();
Condition condition1 = lock.newCondition();
Condition condition2 = lock.newCondition();
Condition condition3 = lock.newCondition();
private int number = 1;

public void sysa(){
lock.lock();
try {
while(number != 1 ) condition1.await();
for (int  i = 1;  i <= 5; i++) {
System.out.println(Thread.currentThread().getName()+"--"+i+"A");
}
number = 2;
condition2.signal();
} catch (Exception e) {
e.printStackTrace();
}finally{
lock.unlock();
}
}

public void sysb(){
lock.lock();
try {
while(number != 2 ) condition2.await();
for (int  i = 1;  i <= 10; i++) {
System.out.println(Thread.currentThread().getName()+"--"+i+"A");
}
number = 3;
condition3.signal();
} catch (Exception e) {
e.printStackTrace();
}finally{
lock.unlock();
}
}

public void sysc(){
lock.lock();
try {
while(number != 3 ) condition3.await();
for (int  i = 1;  i <= 5; i++) {
System.out.println(Thread.currentThread().getName()+"--"+i+"A");
}
System.out.println();
number = 1;
condition1.signal();
} catch (Exception e) {
e.printStackTrace();
}finally{
lock.unlock();
}
}
}
public class MyClass3 {
public static void main(String[] args) {
final ShareSoucre shareSoucre = new ShareSoucre();

new Thread(new Runnable() {
@Override
public void run() {
for(int i = 0; i < 20; i++)shareSoucre.sysa();
}
},"AAA").start();

new Thread(new Runnable() {
@Override
public void run() {
for(int i = 0; i < 20; i++)shareSoucre.sysb();
}
},"BBB").start();

new Thread(new Runnable() {
@Override
public void run() {
for(int i = 0; i < 20; i++)shareSoucre.sysc();
}
},"CCC").start();
}
}
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