Leetcode-Algorithms Hamming Distance(汉明距离)
2017-02-19 13:07
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从今天开始每天用python做几道leetcode的题目练手,从easy到hard递进。
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 231.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
两个integer的汉明距离就是二进制下对应位置不相同的数目。用^运算符后在count 1 的数量即可。
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 231.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
两个integer的汉明距离就是二进制下对应位置不相同的数目。用^运算符后在count 1 的数量即可。
class Solution(object): def hammingDistance(self, x, y): """ :type x: int :type y: int :rtype: int """ return "{0:b}".format(x^y).count("1")
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