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Spring 简单入门实例

2017-01-20 10:02 495 查看
首先新建一个Web 项目
导入相应Jar 包


<?xml version="1.0" encoding="UTF-8"?>
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<bean id="say" class="com.hh.spring.SpringTest">
<property name="name" value="张嘎"></property>
<property name="content" value="三天不打小鬼子,手都痒痒!"></property>
</bean>

</beans>


  

package com.hh.spring;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

public class SpringTest {

private String name;

private String content;

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public String getContent() {
return content;
}

public void setContent(String content) {
this.content = content;
}

private void say(){
System.out.println(name+"说:"+content);
}

public static void main(String[] args) {
ApplicationContext ctx = new ClassPathXmlApplicationContext("applicationContext.xml");
SpringTest zhangGa = ctx.getBean("say",SpringTest.class);
zhangGa.say();
}
}


  
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