MongoDB 模糊查询的三种实现方式-morphia实现

http://gaozzsoft.iteye.com/blog/1561781

MongoDB 模糊查询的三种实现方式-morphia实现如下：

方式一：正则表达式-单个值模糊查询

 

 

Pattern pattern = Pattern.compile("^" + treeIndex + ".*$", Pattern.CASE_INSENSITIVE);

assetInfoDao.createQuery().filter("treeIndexes", pattern);

方式二：正则表达式-多个值模糊查询

 

String[] categorys = category.split(",");

List<Pattern> patterns = Lists.newArrayList();

for (String treeIndex : categorys) {

Pattern pattern = Pattern.compile("^" + treeIndex + ".*$", Pattern.CASE_INSENSITIVE);

patterns.add(pattern);

}

query.filter("treeIndexes all", patterns);

方式三：contains模糊查询方式

 

if (StringUtils.isNotBlank(title)) {

query = query.field("title").contains(title);

}

方式四：精确查询

 

String[] categorys = category.split(",");

query.filter("treeIndexes all", Arrays.asList(categorys));

 

imports:

import java.util.regex.Pattern;

import com.google.code.morphia.DatastoreImpl;

import com.google.code.morphia.query.Query;

 

PS:

/**

 * <p>Create a filter based on the specified condition and value.

 * </p><p>

 * <b>Note</b>: Property is in the form of "name op" ("age >").

 * </p><p>

 * Valid operators are ["=", "==","!=", "<>", ">", "<", ">=", "<=", "in", "nin", "all", "size", "exists"]

 * </p>

 * <p>Examples:</p>

 * 

 * <ul>

 * <li>{@code filter("yearsOfOperation >", 5)}</li>

 * <li>{@code filter("rooms.maxBeds >=", 2)}</li>

 * <li>{@code filter("rooms.bathrooms exists", 1)}</li>

 * <li>{@code filter("stars in", new Long[]{3,4}) //3 and 4 stars (midrange?)}</li>

 * <li>{@code filter("age >=", age)}</li>

 * <li>{@code filter("age =", age)}</li>

 * <li>{@code filter("age", age)} (if no operator, = is assumed)</li>

 * <li>{@code filter("age !=", age)}</li>

 * <li>{@code filter("age in", ageList)}</li>

 * <li>{@code filter("customers.loyaltyYears in", yearsList)}</li>

 * </ul>

 * 

 * <p>You can filter on id properties <strong>if</strong> this query is

 * restricted to a Class<T>.

 */