用小于等于n元去买100只鸡，大鸡5元/只，小鸡3元/只，还有一种1/3元/只得小鸡，分别记为下，x,y,z只，编程求解x,y,z所有可能解

/*****************************************************
copyright (C), 2014-2015, Lighting Studio. Co.,     Ltd.
File name：
Author：Jerey_Jobs    Version:0.1    Date:
Description：
Funcion List:
*****************************************************/

#include <stdio.h>
#include <string.h>
int main()
{
int x = 0,y = 0,z = 0;
int money;
int flag = 1;
int i = 0;
int total = 0;

while(flag)
{
printf("Please enter the money (300 - 500): ");
scanf("%d",&money);
if((money < 300) || (money > 500))
{
flag = 1;
}
else
{
flag = 0;
}
}

//printf("The money is %d\n",money);

//while(total <= money)
//{
for(x = 0;x <= 100;x++)
{
for(y = 0;y <= 100;y++)
{
for(z = 0;z <= 100;z = z + 3)
{
if((x + y + z) == 100)
{
total = 5 * x + 3 * y + (1 / 3) * z;
if(total <= money)
{
printf("x = %2d\ty = %2d\tz = %2d\t",x,y,z);
i++;
if((i % 4) == 0)
{
printf("\n");
}
}
}
}
}
}
//}
printf("\nthere are %d kinds of type\n",i);

return 0;
}