您的位置:首页 > 数据库

对应SQL数据库 关系转对象,表名-类名 ,列名-属性, DeskInfo餐桌类

2016-11-12 12:25 190 查看
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace _03大项目
{
public class DeskInfo
{
//DeskId, DeskName, DeskNamePinYin, DeskDelFlag, DeskNum

private int _deskId;
/// <summary>
/// 餐桌的id
/// </summary>
public int DeskId
{
get { return _deskId; }
set { _deskId = value; }
}
private string _deskName;
/// <summary>
/// 餐桌的名字
/// </summary>
public string DeskName
{
get { return _deskName; }
set { _deskName = value; }
}
private string _deskNamePinYin;
/// <summary>
/// 餐桌的拼音
/// </summary>
public string DeskNamePinYin
{
get { return _deskNamePinYin; }
set { _deskNamePinYin = value; }
}
private int _deskDelFlag;
/// <summary>
/// 删除标识 0---未删除,1----删除的
/// </summary>
public int DeskDelFlag
{
get { return _deskDelFlag; }
set { _deskDelFlag = value; }
}
private string _deskNum;
/// <summary>
/// 餐桌的编号
/// </summary>
public string DeskNum
{
get { return _deskNum; }
set { _deskNum = value; }
}
}
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签:  数据库 sql C# 对象