java.lang.NumberFormatException: Invalid int: ""的解决方法
2016-08-17 13:21
716 查看
java.lang.NumberFormatException: Invalid int: ""不能成功转成int类型错误代码:
private int allCount; String temp = null; allCount = Integer.parseInt(temp);
更改代码(添加try catch使之兼容性增强):
try { String temp = null; allCount = Integer.parseInt(temp); } catch (Exception e) { allCount = 200; }
相关文章推荐
- Android中关于String转int遇到的java.lang.NumberFormatException: Invalid int: "5000.00"错解决办法
- Android报错:java.lang.NumberFormatException: Invalid int: "15112340003"
- aes 解密出现 java.lang.NumberFormatException: Invalid int: "ch"
- java.lang.NumberFormatException: Invalid int: ""
- android java.lang.NumberFormatException: Invalid int: ""
- com.google.gson.JsonSyntaxException: java.lang.NumberFormatException: Invalid double: ""
- 解决:java.lang.NumberFormatException: For input string: "id"
- 已解决java.lang.NumberFormatException: For input string: "7006@17006"
- java.lang.NumberFormatException: Invalid double: "�"
- 执行Hive时出现org.apache.hadoop.util.RunJar.main(RunJar.java:136) Caused by: java.lang.NumberFormatException: For input string: "1s"错误的解决办法(图文详解)
- com.google.gson.JsonSyntaxException: java.lang.NumberFormatException: Invalid double: ""
- java.lang.NumberFormatException: Invalid double: ""
- java.lang.NumberFormatException: null的解决方法
- 如何解决异常:java.lang.NumberFormatException: For input string: "null"
- 已解决java.lang.NumberFormatException: For input string: "7006@17006"
- Java 数据转换报Caused by: java.lang.NumberFormatException: Invalid double: "xxx"
- Struts2访问验证码异常解决OgnlValueStack:64 - ..java.lang.NumberFormatException: For input string: "1494056190
- Caused by: java.lang.NumberFormatException: Invalid double: ""
- ZooKeeper 启动报错 Invalid arguments, exiting abnormally java.lang.NumberFormatException: 的解决办法
- java.lang.NumberFormatException: For input string: "9004@19004" 的解决办法