编程实现：每瓶汽水1元，两个空瓶可以置换一瓶汽水，现在有20元，最多能喝多少瓶汽水

#include <stdio.h>
#include <stdlib.h>
int main()
{
int money = 20;
int count = 20;
while (1)
{
if (money % 2 != 0)
{
count = count + money - 1;
break;
}
else
{
money = money / 2;
count += money;
}
}
printf("%d\n", count);
system("pause");
return 0;
}

#include <stdio.h>
#include <stdlib.h>
int main()
{
int money = 0;
int count = 0;
scanf("%d",&money);
count = 2 * money - 1;
printf("%d\n", count);
system("pause");
return 0;
}