查询数据库中的表名、属性值及其数据类型

查询数据库结构信息：

表名　　=case when a.colorder=1 then d.name else '' end,
表说明 =case when a.colorder=1 then isnull(f.value,'') else '' end,
字段序号=a.colorder,
字段名 =a.name,
标识　　=case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,
主键　　=case when exists(SELECT 1 FROM sysobjects where xtype='PK' and parent_obj=a.id and name in (
　　　　 SELECT name FROM sysindexes WHERE indid in(
　　　　 SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid
　　　 　))) then '√' else '' end,
类型　　=b.name,
占用字节数=a.length,
长度　　=COLUMNPROPERTY(a.id,a.name,'PRECISION'),
小数位数=isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
允许空 =case when a.isnullable=1 then '√'else '' end,
默认值 =isnull(e.text,''),
字段说明=isnull(g.[value],'')

example:

SELECT
FROM syscolumns a
left join systypes b on a.xusertype=b.xusertype
inner join sysobjects d on a.id=d.id  and d.xtype='U' and  d.name<>'dtproperties'
left join syscomments e on a.cdefault=e.id
left join sysproperties g on a.id=g.id and a.colid=g.smallid
left join sysproperties f on d.id=f.id and f.smallid=0
--where d.name='要查询的表'    --如果只查询指定表,加上此条件
order by a.id,a.colorder

View Code

SQL2000系统表的应用：

获取当前数据库的所有表名称

select Name from sysobjects where xtype='u' and statu>=0

获取某一个表的所有字段

select name from syscolumns where id = object_id('表名')

查看与某个表相关的视图、存储过程、函数

select a.* from sysobjects a,syscomments b where a.id =b.id and b.text like'%表名'

查看当前数据库中所有存储过程

select name as存储过程名称 from sysobjects where xtype = 'P'

查询用户创建的所有数据库

select * from master..sysdatabases D where sid not in(select sid from master..syslogins where name='sa')

查询某一个表的字段和数据类型

select column_name,data_type from information_schema.columns
where table_name = '表名'

取得表字段的描述

select name,
(select value from sysproperties where id = syscolumns.id and smallid=syscolumns.colid) as 描述
from syscolumns where id=object_id('表名')

所有表的所有字段的类型

select   c.Name   as   TableName,b.name   as   ColName,a.name   as   Type,a.length
from   syscolumns   a,systypes   b,sysobjects
c   where   c.type= 'U '   and
a.xtype=b.xtype   and   a.id=c.id