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Count and Say

2016-07-16 14:54 323 查看
题目描述:

The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...


1
 is read off as 
"one
1"
 or 
11
.
11
 is read off as 
"two
1s"
 or 
21
.
21
 is read off as 
"one
2
, then 
one 1"
 or 
1211
.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

AC代码如下:

class Solution {
public:
string countAndSay(int n) {
string ans = "1";
if (n <= 0) return string();
for (int i = 0; i < n - 1; i++){
int length = ans.size();
string tmp = "";
int count = 1;
for (int j = 1; j < length; j++){
if (ans[j] == ans[j - 1]){
count++;
}
else{
char ch = ans[j - 1];
char cc = '0' + count;
tmp = tmp + cc + ch;
count = 1;
}
}
char ch = ans[length - 1];
char cc = '0' + count;
tmp = tmp + cc + ch;
ans = tmp;
}
return ans;
}
};
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标签:  LeetCode Count and Say C++