Linked List Cycle
2016-07-15 18:01
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一、问题描述
Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
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二、思路
快慢指针,注意考虑边界
三、代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
if(head == NULL || head -> next == NULL)
return false;
if(head -> next == head)
return true;
ListNode *fast = head -> next -> next;
ListNode *slow = head -> next;
while(fast != slow && fast != NULL && fast -> next != NULL){
fast = fast -> next -> next;
slow = slow -> next;
if(fast == slow)
return true;
}
return false;
}
};
Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
Subscribe to see which companies asked this question
二、思路
快慢指针,注意考虑边界
三、代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
bool hasCycle(ListNode *head) {
if(head == NULL || head -> next == NULL)
return false;
if(head -> next == head)
return true;
ListNode *fast = head -> next -> next;
ListNode *slow = head -> next;
while(fast != slow && fast != NULL && fast -> next != NULL){
fast = fast -> next -> next;
slow = slow -> next;
if(fast == slow)
return true;
}
return false;
}
};
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