【C++】 求两string日期间隔天数

#include <iostream>

#include <string>

#include <stdlib.h>

using namespace std;

const int MOUTHDAYS[12]{31,28,31,30,31,30,31,31,30,31,30,31};

//返回某年某月天数

int inline MouthDays(int mouth,int year)

{

if(year%4 == 0)

if(mouth == 2)

return 29;

return  MOUTHDAYS[mouth-1];

}

//将string转为3个int值

void inline Transformation(string str,int &year,int &mouth,int &day)

{

int flag1 = str.find("/");

year = atoi(str.substr(0,flag1).c_str());

str = str.substr(flag1+1);

int flag2 = str.find("/");

mouth = atoi(str.substr(0,flag2).c_str());

str = str.substr(flag2+1);

day = atoi(str.c_str());

}

int DataMinus(string str1,string str2)

{

int year1,year2;

int mouth1,mouth2;

int day1,day2;

Transformation(str1,year1,mouth1,day1);

Transformation(str2,year2,mouth2,day2);

int num = 0;//总天数统计

//统一日期

num += MouthDays(mouth1,year1)-day1;

mouth1++;

num += day2;

//统一月份

for(int i = mouth1;i<=12;i++)

num += MouthDays(i,year1);

year1++;

for(int i = mouth2-1;i>=1;i--)

num += MouthDays(i,year2);

//按年份计算天数

for(int i = year1;i<year2;i++)

{

if(i%4 == 0)

num += 366;

else

num += 365;

}

return num;

}

int main()

{

string str1("1996/8/24");

string str2("2016/4/12");

cout << DataMinus(str1,str2) << endl;

return 0;

}