【解决方案】cvc-complex-type.2.4.a: Invalid content was found starting with element 'init-param'. One of '{"http://java.sun.com/xml/ns/javaee":run-as, "http://java.sun.com/xml/ns/javaee":security-role-r
2016-05-30 12:18
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【JAVA错误】
cvc-complex-type.2.4.a: Invalid content was found starting with element 'init-param'. One of '{"http://java.sun.com/xml/ns/javaee":run-as, "http://java.sun.com/xml/ns/javaee":security-role-r
【错误源码】
在springmvc 配置过程中,配置web.xml 中报出异常:
异常代码如下:
【解决方案】
错误点:
将代码中
<load-on-startup>1</load-on-startup>
放在<init-param>标签之下即可:
cvc-complex-type.2.4.a: Invalid content was found starting with element 'init-param'. One of '{"http://java.sun.com/xml/ns/javaee":run-as, "http://java.sun.com/xml/ns/javaee":security-role-r
【错误源码】
在springmvc 配置过程中,配置web.xml 中报出异常:
异常代码如下:
<?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <display-name></display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <!-- 配置springmvc核心控制器 --> <servlet> <servlet-name>springmvc</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <!-- 再启动web容器的时候,实例化servlet对象 --> <load-on-startup>1</load-on-startup> <init-param> <param-name>configLocation</param-name> <param-value>classpath:springmvc.xml</param-value> </init-param> </servlet> <servlet-mapping> <servlet-name>springmvc</servlet-name> <url-pattern>*.do</url-pattern> </servlet-mapping> </web-app>
【解决方案】
错误点:
<load-on-startup>1</load-on-startup> <init-param> <param-name>configLocation</param-name> <param-value>classpath:springmvc.xml</param-value> </init-param>
将代码中
<load-on-startup>1</load-on-startup>
放在<init-param>标签之下即可:
<init-param> <param-name>configLocation</param-name> <param-value>classpath:springmvc.xml</param-value> </init-param> <!-- 关键点 --> <load-on-startup>1</load-on-startup>
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