Oracle与SQL-Server数据库SQL"树查询"对比[按照父子节点关系递归拼接]

With SubQuery (upmaterialnumber,qty,subPartNo,SumDrawingNumber) AS
(Select
R.upmaterialnumber,
R.qty, R.materialnumber as subPartNo,
C.SumDrawingNumber as SumDrawingNumber
From ERP_D_MeterialRelation R,ERP_D_BillOfMaterial C
Where R.materialnumber = '6A100045'
And R.materialnumber = C.number
Union All
Select
A1.upmaterialnumber,
A1.qty,A1.subPartNo,
B1.SumDrawingNumber
From ERP_D_BillOfMaterial B1,
(Select
A.upmaterialnumber,
A.qty,
A.materialnumber as subPartNo
From ERP_D_MeterialRelation A
Left Join SubQuery B ON A.upmaterialnumber = B.subPartNo) A1
Where A1.subPartNo = B1.Number)
Select * From SubQuery

Select
c.roleName as roleName,
c.menuName as menuName,
convert(varchar(5000),c.funName) as funName
From (
Select
roleName,
(Select name as menuName From t_scl_func where code = supCode) as menuName,
funName =  (stuff((
Select ','  b.funname
From (
Select
r.name as rolename,
m.name as funname,
m.code as code,
m.parent as supCode
From
t_scl_role r,
t_scl_role_func f,
t_scl_func m
Where r.id = f.role_id
And f.func_code = m.code ) b
Where b.rolename = a.rolename
And b.supCode = a.supCode for xml path('')),1,1,''))
From (
Select
r.name as rolename,
m.name as funname,
m.code as code,
m.parent as supCode
From
t_scl_role r,
t_scl_role_func f,
t_scl_func m
Where r.id = f.role_id
And f.func_code = m.code ) a
Group by rolename,supCode) c
Where c.funname is Not Null Order by c.roleName;