HDU 1002 A + B Problem II -- java大法好

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 306140 Accepted Submission(s): 59153



Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using
32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line
between two test cases.

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

import java.math.BigInteger;
import java.util.Scanner;

public class Main {
public static void main(String[] args) {
BigInteger a,b;
int t;
Scanner cin = new Scanner(System.in);
t = cin.nextInt();
for(int i=1;i<=t;i++){
System.out.println("Case"+" "+i+":");
a = cin.nextBigInteger();
b = cin.nextBigInteger();
if(i<t){
System.out.println(a+" + "+b+" = "+a.add(b));
System.out.println();
}
else{
System.out.println(a+" + "+b+" = "+a.add(b));
}
}
}
}