堆排序(java 语言实现)
2016-04-22 11:16
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可以用 数组或者线性表实现 Heap ,关键是理清楚
当前节点的坐标和父节点的坐标以及左右孩子的坐标的关系,比如 当前坐标是 i 其他节点的坐标如何表示。然后就是添加删除的原则。
当前节点的坐标和父节点的坐标以及左右孩子的坐标的关系,比如 当前坐标是 i 其他节点的坐标如何表示。然后就是添加删除的原则。
package com.shan.heapSort; public class Heap<E extends Comparable<E>> { private java.util.ArrayList<E> list = new java.util.ArrayList<E>(); /** Create a default heap */ public Heap() { } /** Create a heap from an array of objects */ public Heap(E[] objects) { for (int i = 0; i < objects.length; i++) { add(objects[i]); } } /** Add a new object into the heap */ public void add(E e) { list.add(e); // Append to the heap int currentIndex = list.size() - 1; while (currentIndex > 0) { int parentIndex = (currentIndex - 1) / 2; E current = list.get(currentIndex); E parent = list.get(parentIndex); if (current.compareTo(parent) > 0) { list.set(parentIndex, current); list.set(currentIndex, parent); currentIndex = parentIndex; } else { break; // the tree is a heap now } } System.out.println(list); } /** Remove root from the heap */ public E remove() { // if the Heap is empty return null if (list.size() == 0) return null; // cached root(the first element of the list), // and then replace it with the last element in the list E removedOject = list.get(0); list.set(0, list.get(list.size() - 1)); list.remove(list.size() - 1); // find the proper place for the current element int currentIndex = 0; while (currentIndex < list.size()) { int leftChildIndex = 2 * currentIndex + 1; int rightChildIndex = 2 * currentIndex + 2; // Find the max between the tow child if (leftChildIndex >= list.size()) // the tree is a heap break; int maxIndex = leftChildIndex; if (rightChildIndex < list.size()) { if (list.get(maxIndex).compareTo(list.get(rightChildIndex)) < 0) { maxIndex = rightChildIndex; } } // Swap if the current node is less then the maximum E current = list.get(currentIndex); E maxChild = list.get(maxIndex); if (current.compareTo(maxChild) < 0) { list.set(maxIndex, current); list.set(currentIndex, maxChild); currentIndex = maxIndex; } else { break; } } return removedOject; } /** Remove the root from the heap */ public E remove2() { if (list.size() == 0) return null; E removedObject = list.get(0); list.set(0, list.get(list.size() - 1)); list.remove(list.size() - 1); int currentIndex = 0; while (currentIndex < list.size()) { int leftChildIndex = 2 * currentIndex + 1; int rightChildIndex = 2 * currentIndex + 2; // Find the maximum between two children if (leftChildIndex >= list.size()) break; // The tree is a heap int maxIndex = leftChildIndex; if (rightChildIndex < list.size()) { if (list.get(maxIndex).compareTo(list.get(rightChildIndex)) < 0) { maxIndex = rightChildIndex; } } // Swap if the current node is less than the maximum if (list.get(currentIndex).compareTo(list.get(maxIndex)) < 0) { E temp = list.get(maxIndex); list.set(maxIndex, list.get(currentIndex)); list.set(currentIndex, temp); currentIndex = maxIndex; } else break; // The tree is a heap } return removedObject; } /*public ArrayList<E> heapSort() { for (int i = 0; i < list.size(); i++) { E temp = list.get(i); list.set(i, this.remove()); } return list; } */ /** Get the number of nodes in the tree */ public int getSize() { return list.size(); } public static void main(String[] args) { Integer[] list = { 2, 1, 3, 5, 0, 12, 34, 22, 89, 11 }; Heap<Integer> heap = new Heap<>(list); for (int i = list.length - 1; i >=0; i--) { //System.out.print(heap.remove() + " "); list[i] = heap.remove(); } for (int i = 0; i < list.length; i++) { System.out.print(list[i] + " "); } } }
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