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Hibernate中的sql语句中使用分组查询

2016-04-11 15:30 459 查看
1.我的应用场景: 优化一个分组查询
数据库里面有一张表message(故障表),包括的字段有message_id(故障编码),app_id(项目编码),msg_status(故障状态:0表示未处理,1表示进行中,2表示已完成,3表示未派发, 4表示已派发);还有一张表message_user(人员表),包括的字段有message_id(故障编码),user_name(故障处理人),其中messag_id是来自表message的外键。 现在需要一个方法在指定故障处理人和项目编码的情况下查询出各种故障状态下面的数量。

2.代码修改前后的思路对比

修改前:分别查询,根据传入的msg_status的值分别查询,故每种状态都要去数据库查询一次,效率低。

dao层的方法

Integer getMsgStatusCount(Integer msgStatus, String userName, String projectCode);//projectCode就是app_id

hql语句为:

String hql = "select count(m) from Message m where m.msgStatus= " + msgStatus + " and m.messageId in"+
"(select mu.messageId from MessageUser mu where mu.userName like '%"+userName+"%' "+
" and m.appId = '"+projectCode+"')"+
"and m.msgType = '" + Constants.MALF_TYPE_MALF + "';

service层的方法

Map<String, Integer> getMalfunctionStatus(String userName,  String projectCode);

所以每次查询service层都要调用dao层的方法4次:

Integer initMsgCount = messageDao.getMsgStatusCount(Constants.MSG_STATUS_INIT, userName, projectCode);
Integer processingMsgCount = messageDao.getMsgStatusCount(Constants.MSG_STATUS_PROCESSING, userName, projectCode);
Integer completedMsgCount = messageDao.getMsgStatusCount(Constants.MSG_STATUS_COMPLETED, userName, projectCode);
Integer unAssignedCount = messageDao.getMsgStatusCount(Constants.MSG_STATUS_UNASSIGNED, userName, projectCode);
Integer assignedMsgCount = messageDao.getMsgStatusCount(Constants.MSG_STATUS_ASSIGNED, userName, projectCode);

修改后:其实只用一个分组查询可以

dao层的sql语句改为:

String sql = "SELECT m.msg_status as status, COUNT(m.msg_status) as num FROM message m WHERE m.message_Id IN (SELECT mu.message_Id    FROM message_user mu WHERE mu.user_name = '"+ userName +"' “+
" AND mu.app_id = '"+ projectCode +"')"+
" AND m.msg_type = '"+ Constants.MALF_TYPE_MALF +"' "+
" GROUP BY m.msg_status";

3.修改时遇到的问题

①开始不知道怎么获得结果,以前的查询,比如使用*获得一个实体的list,而这里查询的是一个字段和一个聚合函数的结果,然后参考了别人的代码,用到了方法

setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP),使用这个方法后就可以根据查询的字段名取相应的值

②java.math.BigInteger和java.lang.Integer之间不能直接转换

开始用Map<String, Integer>来接收查询的num,一直报java.math.BigInteger不能转为java.lang.Integer,后来参考别人的代码用Map<String, Object>来接收,然后利用 Object的toString()方法转为String,然后用Integer的parsenInt()方法转为Integer就可以了

<span><span>//最后的dao层代码:</span></span>
@SuppressWarnings("unchecked")
public List<Map<String, Object>> getMsgStatusCount(String userName,
String projectCode){
StringBuffer sql = new StringBuffer();
sql.append("SELECT m.msg_status as status, COUNT(m.msg_status) as num FROM message m WHERE m.message_Id IN (SELECT mu.message_Id FROM message_user mu WHERE mu.user_name = '"+ userName +"' ");
//    	hql.append("SELECT * FROM Message m WHERE m.messageId IN (SELECT mu.messageId FROM MessageUser mu WHERE mu.userName = '"+ userName +"' ");
if(StringUtils.isNotBlank(projectCode)){
sql.append(" AND mu.app_id = '"+ projectCode +"')");
}
sql.append(" AND m.msg_type = '"+ Constants.MALF_TYPE_MALF +"' ");
sql.append(" GROUP BY m.msg_status");

Query query = getSession().createSQLQuery(sql.toString());
query.setResultTransformer(Transformers.ALIAS_TO_ENTITY_MAP);
List<Map<String, Object>> msgStatusCountList = new ArrayList<Map<String, Object>>();
List list = query.list();
for (int i = 0; i < list.size(); i++) {
Map<String, Object> obj = (Map<String, Object>) list.get(i);
msgStatusCountList.add(obj);
}

return msgStatusCountList;

//最后service层的部分代码
List<Map<String, Object>> msgStatusCountList = messageDao.getMsgStatusCount(userName, projectCode);
for (int i = 0; i < msgStatusCountList.size(); i++) {
if(msgStatusCountList.get(i).get("status").toString().equals("1")){
processingMsgCount = Integer.parseInt(msgStatusCountList.get(i).get("num").toString());
}
if(msgStatusCountList.get(i).get("status").toString().equals("2")){
completedMsgCount = Integer.parseInt(msgStatusCountList.get(i).get("num").toString());
}
if(msgStatusCountList.get(i).get("status").toString().equals("3")){
unAssignedCount = Integer.parseInt(msgStatusCountList.get(i).get("num").toString());
}
if(msgStatusCountList.get(i).get("status").toString().equals("4")){
assignedMsgCount = Integer.parseInt(msgStatusCountList.get(i).get("num").toString());
}
}
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