1152: 【C语言训练】计算：t=1-1/(2*2)-1/(3*3)-...-1/(m*m)

#include<stdio.h>
int main()
{
double t=1;
int m, i = 2;
scanf("%d", &m);
if (m == 1||m==-1)
printf("%.6f", t);
else
{
if (m < 0)
m = 0 - m;
while (i <= m)
{
t = t - 1.0 / (i*i);
i++;
}
}
printf("%.6f\n", t);
return 0;
}