C语言实现时间的加一天或者减一天

转换思路利用time_t类型来进行时间的换算。

#include
<stdio.h>
#include
<string.h>
#include
<stdlib.h>
#include
<string>
#include
<time.h>

using std::string;
#pragma
warning(disable:4996)
int main()
{
string
_strDealDate("20120124");
charszDate[20]= { 0 };
intYear= 0,
Month = 0, Day= 0,
Hour = 0, Min= 0,
Second = 0;

strcpy(szDate, (char*)_strDealDate.substr(0,
4).c_str());
printf("%s\n",szDate);

//获取当前时间
time_t
curTime = time(NULL);

structtm*
t= localtime(&curTime);

printf("%4d %02d %02d\n",
t->tm_year+ 1900,
t->tm_mon+ 1,
t->tm_mday);//获取当前的日期
printf(
"%02d %02d %02d\n",t->tm_hour,t->tm_min,t->tm_sec);
// 获取当前的时间

//获取减一天后的时间
time_t
preDay = curTime- 3600 * 24;

t= localtime(&preDay);
printf("%4d %02d %02d\n",
t->tm_year+ 1900,
t->tm_mon+ 1,
t->tm_mday);//获取前一天的日期
printf("%02d %02d %02d\n",t->tm_hour,t->tm_min,t->tm_sec);
// 获取前一天的时间

//获取加一天后的时间
time_t
preDay = curTime+ 3600 * 24;

t= localtime(&preDay);
printf("%4d %02d %02d\n",
t->tm_year+ 1900,
t->tm_mon+ 1,
t->tm_mday);//获取一天后的日期
printf("%02d %02d %02d\n",t->tm_hour,t->tm_min,t->tm_sec);
// 获取一天后的时间

return0;
}

运行结果