Shell特殊变量：$*和$@的区别

$* 和 $@ 都表示传递给函数或者脚本的所有参数，不被双引号(" ")包含时，两者效果相同，都以"$1" "$2" … "$n" 的形式输出所有参数。

但是当它们被双引号(" ")包含时，"$*" 会将所有的参数作为一个整体，以"$1 $2 … $n"的形式输出所有参数；"$@" 会将各个参数分开，以"$1" "$2" … "$n" 的形式输出所有参数。

例如：

#!/bin/bash
echo "\$*=" $*
echo "\"\$*\"=" "$*"

echo "\$@=" $@
echo "\"\$@\"=" "$@"

echo "print each param from \$*"
for var in $*
do
echo "$var"
done

echo "print each param from \$@"
for var in $@
do
echo "$var"
done

echo "print each param from \"\$*\""
for var in "$*"
do
echo "$var"
done

echo "print each param from \"\$@\""
for var in "$@"
do
echo "$var"
done

执行 ./test.sh "a" "b" "c" "d"，看到下面的结果：

$*= a b c d

"$*"= a b c d

$@= a b c d

"$@"= a b c d

print each param from $*

a

b

c

d

print each param from $@

a

b

c

d

print each param from "$*"

a b c d

print each param from "$@"

a

b

c

d