leetcode 24. Swap Nodes in Pairs
2016-03-25 12:10
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1.题目
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
2.思路
画个图就方便理解了。
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
ListNode* newhead = new ListNode(-1);
newhead->next = head;
ListNode* pre = newhead;
ListNode* cur = head;
while(cur && cur->next){
pre->next = cur->next;
cur->next = cur->next->next;
pre->next->next = cur;
pre = cur;
cur = cur->next;
}
return newhead->next;
}
};
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given
1->2->3->4, you should return the list as
2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
2.思路
画个图就方便理解了。
class Solution {
public:
ListNode* swapPairs(ListNode* head) {
ListNode* newhead = new ListNode(-1);
newhead->next = head;
ListNode* pre = newhead;
ListNode* cur = head;
while(cur && cur->next){
pre->next = cur->next;
cur->next = cur->next->next;
pre->next->next = cur;
pre = cur;
cur = cur->next;
}
return newhead->next;
}
};
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