Leetcode: 190. Reverse Bits(JAVA)
2016-03-13 11:18
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【问题描述】
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
【思路】
类似于整数反转,首先按位与取最后一位后,依次右移1位。同时将结果左移1位,按位或。
【代码】
public class Solution {
// you need treat n as an unsigned value
public int reverseBits(int n) {
int result = 0;
int i = 0;
while (i < 32) {
int temp = n & 0x01;
n = n >> 1;
result = (result << 1) | temp;
i++;
}
return result;
}
}
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
【思路】
类似于整数反转,首先按位与取最后一位后,依次右移1位。同时将结果左移1位,按位或。
【代码】
public class Solution {
// you need treat n as an unsigned value
public int reverseBits(int n) {
int result = 0;
int i = 0;
while (i < 32) {
int temp = n & 0x01;
n = n >> 1;
result = (result << 1) | temp;
i++;
}
return result;
}
}
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